【发布时间】:2016-11-05 21:07:44
【问题描述】:
我有一个应该显示报表查看器的 Web 应用程序。这是我的步骤:
1) 将脚本管理器和报表查看器添加到新的 Web 表单
2) 添加报表并将其绑定到名为 dataset1 的数据集
3) 为查询创建参数
4) 为网络表单编写代码...
private DataTable GetData(Int64 id_doc)
{
DataTable dt = new DataTable();
string connStr = System.Configuration.ConfigurationManager.ConnectionStrings["ConnectionStringloginDb"].ConnectionString;
try
{
using (var conn = new MySqlConnection(connStr))
{
string sSQL = "select * from details_doc where id_doc=@id_doc";
MySqlCommand cmd = new MySqlCommand(sSQL, conn);
cmd.CommandType = CommandType.Text;
cmd.Parameters.Add(new MySqlParameter("@id_doc", Session["id_doc"].ToString()));
MySqlDataAdapter adp = new MySqlDataAdapter(cmd);
adp.Fill(dt);
}
}
catch (Exception)
{
throw;
}
return dt;
}
protected void showReport()
{
DataTable dt = GetData(Convert.ToInt64(Session["id_doc"].ToString()));
rptViewer.LocalReport.Refresh();
rptViewer.Reset();
rptViewer.LocalReport.EnableExternalImages = true;
this.rptViewer.ProcessingMode = Microsoft.Reporting.WebForms.ProcessingMode.Local;
ReportDataSource rds = new ReportDataSource("DataSet1", dt);
rptViewer.LocalReport.DataSources.Add(rds);
rptViewer.LocalReport.ReportPath = "ReportInvoice.rdlc";
ReportParameter rptParam = new ReportParameter("ReportParameter1", Session["id_doc"].ToString());
rptViewer.LocalReport.SetParameters(rptParam);
rptViewer.LocalReport.Refresh();
}
protected void Page_Load(object sender, EventArgs e)
{
if (!Page.IsPostBack){
if (Session["id_doc"] != null)
{
GetData(Convert.ToInt64(Session["id_doc"]));
mostraReport();
}
}
}
现在代码工作得很好,但我需要报告显示另一个,第二个表。我将添加另一个数据集和另一个报告参数,但后来我被代码卡住了。任何帮助将不胜感激。
【问题讨论】:
标签: c# asp.net dataset reportviewer multiple-tables