为什么这个猜数字程序不继续越过这条线？

Question

以下代码用于猜数字游戏。它没有错误，但没有给出输出。如何进一步改进代码？

它一直工作到print("Your Number has been Generated,Enter your guess Below") 这一行，但没有给出任何输出。

     #Guess the number

     from random import randint

     print("Welcome to Guess the Number Game:")
     print("Press 'g' to Generate Number between 0 and 100:")

     cmd=input("->")

    if cmd=='g':
       num=randint(0,100)
    else:
       print("Unknown Input")


    def chk(x):
        if int(x)==True:
           chk=True
        else:
           chk=False

    def diff(x,y):
        diff=(x-y)
        return diff

    print("Your Number has been Generated,Enter your guess Below")
    guess=input("->")

    chk(guess)

    while chk==True:
    diff(num,guess)
    if diff==0:
    print("Congrats! correct Guess")

    elif diff>10:
    print("Oh! too high")

    elif diff<5 and diff>0:
    print("very close!Better Luck Next time")

    else:
    diff<0
    print("Sorry!too Low")

Answer 1

已经给出了很好的答案，但是您可以使用非常“扁平”的脚本来做到这一点，而无需定义函数。这仅作为示例：

from random import randint

# welcome
print("Welcome to Guess the Number Game:")

# loop until 'g' is given
cmd = ''
while not cmd == 'g':
    print("Press 'g' and '<enter>' to Generate Number between 0 and 100:")
    cmd = input("->")       

# generates a random number
num = randint(0,100)
print("Your Number has been Generated,Enter your guess Below")

# loops until correct answer is guessed
while True:
    try:
        guess=int(input("guess->"))
    except ValueError:
        print('Numbers only please')
        continue
    if guess > num: 
        print('too high')
    if guess < num: 
        print('too low')        
    if guess == num:
        print("Congrats! correct Guess")
        break

Answer 2

您有几个问题，其中一些可能是转录问题：

def chk(x):
    if int(x)==True:
       chk=True
    else:
       chk=False

我想这是为了check 输入。根据 python 的版本，这将始终将 chk 设置为 false。这是因为int 返回一个整数，它与布尔值True 的类型不同。目前尚不清楚您要在这里实现什么。看起来您想检查输入是否为数字。相反，为什么不使用isdigit？因为，目前，您的代码返回 false 您永远不会进入 while 循环

您的 while 循环也没有正确缩进，根据经验，if 和 while 语句之类的语句之后需要换行和缩进。

所以这可能是更好的代码：

# keep guessing while it's a digit
while guess.isdigit():
    # assign the difference to a variable
    # don't forget to indent after the while statement
    diff = diff(num, int(guess))
    if diff==0:
        # indent again!
        print("Congrats! correct Guess")

    elif diff>10:
        print("Oh! too high")

    elif diff<5 and diff>0:
        print("very close!Better Luck Next time")

    elif diff<0:
        print("Sorry!too Low")

这样你就根本不需要chk。

Answer 3

有多个问题，我已经使用 cmets 展示了这一点

from random import randint

print("Welcome to Guess the Number Game:")
print("Press 'g' to Generate Number between 0 and 100:")

cmd=input("->")

if cmd=='g':
       num=randint(0,100)
else:
       print("Unknown Input")


def chk(x):
    if x.isnumeric(): # needs to be '.isNumeric()' as only the only integer that will return true is '1'
           chk=True
    else:
            chk=False
    return chk #Returns Boolean

def diff(x,y):
        return (y-x)# this needs to y-x to be correct

print("Your Number has been Generated,Enter your guess Below")
guess=input("->")

while chk(guess): #or chk(guess) == True
    difference = diff(num,int(guess))#guess needs to be an INTEGER
    if difference==0:
        print("Congrats! correct Guess")
        exit()

if difference>10:
    print("Oh! too high")

elif difference<5 and difference>0:
    print("very close!Better Luck Next time")

elif difference<0:
    print("Sorry!too Low")
print("Enter your guess Below")#allows you to put in another guess
guess=input("->")#sets the guess variable
chk(guess)