Python Selenium 等到任何文本

Question

我有一个 selenium 测试，需要等到任何文本被填充，而不是精确的文本字符串匹配......

我了解到text_to_be_present_in_element、text_to_be_present_in_element_value 可用于此类用途，但我可能需要正则表达式之类的东西，而不是完全匹配。

有人可以分享吗？

# exact match.
from selenium.webdriver.support import expected_conditions as EC
wait = WebDriverWait(driver, 10)
element = wait.until(EC.text_to_be_present_in_element((By.Id,'f_name'), '<searchstring>'))

Answer 1

没问题。做一个custom Expected Condition:

import re
from selenium.webdriver.support import expected_conditions as EC

class wait_for_text_to_match(object):
    def __init__(self, locator, pattern):
        self.locator = locator
        self.pattern = re.compile(pattern)

    def __call__(self, driver):
        try:
            element_text = EC._find_element(driver, self.locator).text
            return self.pattern.search(element_text)
        except StaleElementReferenceException:
            return False

用法：

wait = WebDriverWait(driver, 10)
wait.until(wait_for_text_to_match((By.ID, "myid"), r"regex here"))