Scrapy ImportError：无法导入名称“______Item”

Question

我是 python 2.7 和 Scrapy 的新手，从命令行运行“scrapy crawl prop$”时收到以下错误。我认为这是一个简单的修复，因此，非常感谢任何帮助！

错误信息：

  File"C:\Anaconda2\propub\propub\spiders\propub_spider.py", line 4, in <module>
    from propub.items import propubItem
ImportError: cannot import name propubItem

items.py:

import scrapy
from scrapy.item import Item, Field

class PropubItem(scrapy.Item):
    payee = scrapy.Field()
    link = scrapy.Field()
    city = scrapy.Field()
    state = scrapy.Field()
    company = scrapy.Field()
    amount =  scrapy.Field()
    pass

propub_spiders.py:

import scrapy 
from scrapy.contrib.spiders import CrawlSpider, Rule
from scrapy.contrib.linkextractors.sgml import SgmlLinkExtractor 
from propub.items import propubItem

class propubSpider(CrawlSpider):
    name = 'prop$'
    allowed_domains = ['https://projects.org']
    start_urls = [
        'https://projects/search?state%5Bid%5D=33',
        'https://projects/search?page=2&state%5Bid%5D=33',
        'https://projects/search?page=3&state%5Bid%5D=33']

    rules = (Rule(SgmlLinkExtractor(allow=('\\search?page=\\d')), 'parse_start_url', follow=True),)

    def parse(self, response):
        for sel in response.xpath('//*[@id="payments_list"]/tbody'):
            item = propubItem()
            item['payee'] = sel.xpath('tr[1]/td[1]/a[2]/text()').extract()
            item['link'] = sel.xpath('tr[1]/td[1]/a[1]/@href').extract()
            item['city'] = sel.xpath('tr[1]/td[2]/text()').extract()
            item['state'] = sel.xpath('tr[1]/td[3]/text()').extract()
            item['company'] = sel.xpath('tr[1]/td[4]').extract()
            item['amount'] =  sel.xpath('tr[1]/td[7]/span/text()').extract()
            yield item 

Answer 1

这只是一个错字。您的项目类名称​​以大写字母开头。

替换：

from propub.items import propubItem

与：

from propub.items import PropubItem