我已经发布了this solution,但它是在Range(address) 抛出错误的情况下address 超过了一些长度。
但现在的主题严格来说是删除许多行的最快方法,我假设它需要坚持实际 delete 行(即保持格式、公式、公式引用...... )
所以我将再次在此处发布该解决方案(在“按地址删除”方法的标题下)以及第二个(“按排序删除”方法),它要快得多(第一个需要大约 20 秒,第二个处理大约 40k 行需要 0.2 秒,即删除 20k 行)
在 OP For icount = endRow To 3 Step -2 之后,这两种解决方案都略微专业化,但可以很容易地使其更通用
“按地址删除”方法
Option Explicit
Sub main()
Dim icount As Long, endrow As Long
Dim strDelete As String
With Worksheets("Delete")
For icount = .Cells(.Rows.Count, "C").End(xlUp).Row To 3 Step -2
strDelete = strDelete & "," & icount & ":" & icount
Next icount
End With
DeleteAddress Right(strDelete, Len(strDelete) - 1)
End Sub
Sub DeleteAddress(ByVal address As String)
Dim arr As Variant
Dim iArr As Long
Dim partialAddress As String
arr = Split(address, ",")
iArr = LBound(arr)
Do While iArr < UBound(arr)
partialAddress = ""
Do While Len(partialAddress & arr(iArr)) + 1 <= 250 And iArr < UBound(arr)
partialAddress = partialAddress & arr(iArr) & ","
iArr = iArr + 1
Loop
If Len(partialAddress & arr(iArr)) <= 250 Then
partialAddress = partialAddress & arr(iArr)
iArr = iArr + 1
Else
partialAddress = Left(partialAddress, Len(partialAddress) - 1)
End If
Range(partialAddress).Delete shift:=xlUp
Loop
End Sub
“按排序删除”方法
Option Explicit
Sub main()
Dim nRows As Long
Dim iniRng As Range
With Worksheets("Delete")
nRows = .Cells(.Rows.Count, "C").End(xlUp).Row
.Cells(1, .UsedRange.Columns(.UsedRange.Columns.Count + 1).Column).Resize(nRows) = Application.Transpose(GetArray(nRows, 3))
With .UsedRange
.Sort key1:=.Columns(.Columns.Count), Header:=xlNo
Set iniRng = .Columns(.Columns.Count).Find(what:=nRows + 1, LookIn:=xlValues, lookat:=xlWhole)
.Columns(.Columns.Count).ClearContents
End With
.Range(iniRng, iniRng.End(xlDown)).EntireRow.Delete
End With
End Sub
Function GetArray(nRows As Long, iniRow As Long)
Dim i As Long
ReDim arr(1 To nRows) As Long
For i = 1 To nRows
arr(i) = i
Next i
For i = nRows To iniRow Step -2
arr(i) = nRows + 1
Next i
GetArray = arr
End Function