如果您愿意,您可以将数据构建为字典,然后可以这样解决,其中每个条目作为属性“性别”,这也是字典 color_map 中的查找键:
import matplotlib.pyplot as plt
fig,ax=plt.subplots(1,1)
data={
0:{"name":"John", "value":5, "gender":"male"},
1:{"name":"Nina", "value":2, "gender":"female"},
2:{"name":"Darren", "value":1, "gender":"male"},
3:{"name":"Peter", "value":7, "gender":"male"},
4:{"name":"Joe", "value":8, "gender":"male"},
5:{"name":"Kendra", "value":12,"gender":"female"},
}
color_map={"male":"b","female":"r"}
xs=data.keys()
ys=[v["value"] for v in data.values()]
names=[v["name"] for v in data.values()]
colors=[color_map[v["gender"]] for v in data.values()]
ax.bar(xs,ys,color=colors)
ax.set_xticks(xs)
ax.set_xticklabels(names)
plt.show()
这里有多种方法可以获得有效的“男性”/“女性”图例;一种是创建一个fully custom legend。例如,您可以将字典分成一个用于男性数据和一个用于女性数据,然后创建两个单独的条形图,例如ax.bar(… , label="male"),但这是一种臃肿的方法。
我建议使用 pandas 库,然后将我的答案更改为:
import matplotlib.pyplot as plt
import pandas as pd
fig,ax=plt.subplots(1,1)
data={
0:{"name":"John", "value":5, "gender":"male"},
1:{"name":"Nina", "value":2, "gender":"female"},
2:{"name":"Darren", "value":1, "gender":"male"},
3:{"name":"Peter", "value":7, "gender":"male"},
4:{"name":"Joe", "value":8, "gender":"male"},
5:{"name":"Kendra", "value":12,"gender":"female"},
}
df=pd.DataFrame.from_dict(data,orient='index')
color_map={"male":"b","female":"r"}
df["colors"]=df["gender"].map(color_map)
for g in ["male","female"]:
xs=df.index[df["gender"]==g]
ys=df["value"][df["gender"]==g]
color=df["colors"][df["gender"]==g]
## or, perhaps easier in this specific case:
# color=color_map[g]
ax.bar(xs,ys,color=color,label=g)
ax.legend()
ax.set_xticks(df.index)
ax.set_xticklabels(df["name"])
plt.show()
在这里,关键是我们可以在各种条件下过滤数据框df(可能认为它像 Excel 工作表),例如df["value"][df["gender"]=="male"]。这样我们就可以轻松创建两个单独的条形图。