Python：TypeError：强制转换为 Unicode：需要字符串或缓冲区，PosixPath

Question

我正在尝试运行此 python 脚本，该脚本试图使用在同一 xslx 中的列中找到的文件名重命名 xslx 文件。 （原脚本找到Here）

import os
from pathlib import Path

import xlrd

def rename_excel_files(path):
    path = Path(path)

    for filename in os.listdir(path):
        file_path = path.joinpath(filename)
        excel_file = xlrd.open_workbook(file_path)
        work_sheet = excel_file.sheet_by_index(1)
        dest_path = path.joinpath(work_sheet.cell_value(20, 0) + '.xlsx')
        os.replace(file_path, dest_path)

if __name__ == '__main__':
     rename_excel_files(r'/Users/User/OQC')

但是在python2运行时出现如下错误：

  File "oqc_rename.py", line 18, in <module>
    rename_excel_files(r'/Users/User/OQC')
  File "oqc_rename.py", line 10, in rename_excel_files
    for filename in os.listdir(path):
TypeError: coercing to Unicode: need string or buffer, PosixPath found

更新：运行 python3 时出现错误：

 File "/Users/user/OQC/oqc_rename.py", line 19, in <module>
    rename_excel_files(r'/Users/user/OQC')
  File "/Users/user/OQC/oqc_rename.py", line 12, in rename_excel_files
    excel_file = xlrd.open_workbook(file_path)
  File "/Library/Frameworks/Python.framework/Versions/3.9/lib/python3.9/site-packages/xlrd/__init__.py", line 148, in open_workbook
    bk = book.open_workbook_xls(
  File "/Library/Frameworks/Python.framework/Versions/3.9/lib/python3.9/site-packages/xlrd/book.py", line 92, in open_workbook_xls
    biff_version = bk.getbof(XL_WORKBOOK_GLOBALS)
  File "/Library/Frameworks/Python.framework/Versions/3.9/lib/python3.9/site-packages/xlrd/book.py", line 1278, in getbof
    bof_error('Expected BOF record; found %r' % self.mem[savpos:savpos+8])
  File "/Library/Frameworks/Python.framework/Versions/3.9/lib/python3.9/site-packages/xlrd/book.py", line 1272, in bof_error
    raise XLRDError('Unsupported format, or corrupt file: ' + msg)
xlrd.biffh.XLRDError: Unsupported format, or corrupt file: Expected BOF record; found b'\x00\x00\x00\x01Bud1'

根据我的搜索，我认为问题可能是我在重命名之前已经打开了文件？ 确认 xlsx 文件没有损坏。 但是，我不确定如何解决这个问题，因为我是一个 python 菜鸟。

提前致谢！

Answer 1

xlrd.open_workbook 期待一个字符串，只需将 Path 对象表示为一个，它应该很高兴

-xlrd.open_workbook(path)
+xlrd.open_workbook(str(path))

请注意官方文档说不支持非.xls 文件： https://pypi.org/project/xlrd/

此库将不再读取 .xls 文件以外的任何内容。有关读取较新文件格式的替代方案，请参阅http://www.python-excel.org/。