地理位置观察位置距离计算器

Question

我正在使用地理定位来获取用户的当前位置并使用 watchPosition 方法对其进行监控。但是，有没有办法计算用户起始位置和当前位置之间的距离？以下是我的代码：

var x = document.getElementById("info");

function getLocation() {
    if(navigator.geolocation) {
        navigator.geolocation.watchPosition(showPosition, showError, {
            enableHighAccuracy: true,
            maximumAge: 60000,
            timeout: 27000
        })
    } else {
        x.innerHTML = "Geolocation is not supported by this browser.";
    }
}
var flightPathCoordinates = [];

function showPosition(position) {
    x.innerHTML = "Latitude: " + position.coords.latitude + "<br>Longitude: " + position.coords.longitude + "<br>Accuracy: " + position.coords.accuracy + "<br>Altitude: " + position.coords.altitude + "<br>Altitude Accuracy: " + position.coords.altitudeAccuracy + "<br>Heading: " + position.coords.heading + "<br>Speed: " + position.coords.speed + "<br>Speed (mph): " + position.coords.speed * 2.2369 + "<br>Speed (km): " + position.coords.speed * 3.6 + "<br>Timestamp: " + new Date(position.timestamp).toLocaleString() + "<br>Distance Travelled (km): " + calculateDistance(position.coords.latitude, position.coords.longitude, position.coords.latitude, position.coords.longitude);
    // Distance Calculator

    function calculateDistance(lat1, lon1, lat2, lon2) {
        if(typeof (Number.prototype.toRad) === "undefined") {
            Number.prototype.toRad = function () {
                return this * Math.PI / 180;
            }
        }
        var R = 6371; // km
        var dLat = (lat2 - lat1).toRad();
        var dLon = (lon2 - lon1).toRad();
        var a = Math.sin(dLat / 2) * Math.sin(dLat / 2) + Math.cos(lat1.toRad()) * Math.cos(lat2.toRad()) * Math.sin(dLon / 2) * Math.sin(dLon / 2);
        var c = 2 * Math.atan2(Math.sqrt(a), Math.sqrt(1 - a));
        var d = R * c;
        return d;
    }
    Number.prototype.toRad = function () {
        return this * Math.PI / 180;
    }
    lat = position.coords.latitude;
    lon = position.coords.longitude;
    latlon = new google.maps.LatLng(lat, lon)
    mapholder = document.getElementById('mapholder')
    var myOptions = {
        center: latlon,
        zoom: 16,
        mapTypeId: google.maps.MapTypeId.ROADMAP,
        mapTypeControl: true,
        navigationControlOptions: {
            style: google.maps.NavigationControlStyle.SMALL
        }
    }
    var map = new google.maps.Map(document.getElementById("mapholder"), myOptions);

非常感谢任何帮助，因为我对此很陌生。

谢谢！

Answer 1

这已改编自 Google Maps API，并经过重新设计以独立于库。

示例 - 计算从纽约市中心到费城市中心的距离。

• Fiddle for miles: http://jsfiddle.net/DXNzu/
• Fiddle for kilometers: http://jsfiddle.net/DXNzu/1/

JS

function distanceFrom(points) {
    var lat1 = points.lat1;
    var radianLat1 = lat1 * (Math.PI / 180);
    var lng1 = points.lng1;
    var radianLng1 = lng1 * (Math.PI / 180);
    var lat2 = points.lat2;
    var radianLat2 = lat2 * (Math.PI / 180);
    var lng2 = points.lng2;
    var radianLng2 = lng2 * (Math.PI / 180);
    var earth_radius = 3959; // or 6371 for kilometers
    var diffLat = (radianLat1 - radianLat2);
    var diffLng = (radianLng1 - radianLng2);
    var sinLat = Math.sin(diffLat / 2);
    var sinLng = Math.sin(diffLng / 2);
    var a = Math.pow(sinLat, 2.0) + Math.cos(radianLat1) * Math.cos(radianLat2) * Math.pow(sinLng, 2.0);
    var distance = earth_radius * 2 * Math.asin(Math.min(1, Math.sqrt(a)));
    return distance.toFixed(3);
}

var distance = distanceFrom({
    // NYC
    'lat1': 40.713955826286046,
    'lng1': -74.00665283203125,
    // Philly
    'lat2': 39.952335,
    'lng2': -75.163789
});

结果是 80.524 英里或129.583 公里。

Answer 2

你可以使用Haversine公式

rad = function(x) {return x*Math.PI/180;}

distHaversine = function(p1, p2) { // Points are Geolocation.coords objects
  var R = 6371; // earth's mean radius in km
  var dLat  = rad(p2.latitude - p1.latitude);
  var dLong = rad(p2.longitude - p1.longitude);

  var a = Math.sin(dLat/2) * Math.sin(dLat/2) +
          Math.cos(rad(p1.lat())) * Math.cos(rad(p2.lat())) * Math.sin(dLong/2) * Math.sin(dLong/2);
  var c = 2 * Math.atan2(Math.sqrt(a), Math.sqrt(1-a));
  var d = R * c;

  return d.toFixed(3);
}

两个提示

1. typeof 不是函数。像这样使用它：typeof something
2. 不要在监听器中放置 polyfill。每次侦听器触发时，您都在重复 polyfill 操作。