迭代二维列表并根据条件 if 语句删除元素或行 - Python

Question

我有一个二维数组，第一列是一串名称，后面的列是它们的分数（整数）。我正在尝试遍历数组并删除任何大于 100 且小于 0 的分数（单个元素），或者从该数组中删除整行。我是他们试图将删除的分数写入 .txt 文件。

下面的第一个代码迭代一个数组，当我运行它以删除实际行时，它只删除了超过 100 的行，我必须重新运行它以删除元素超过 100 的更多行并且它不会删除元素小于 0 的任何行（因此是负数） int() 方法似乎没有在迭代比较时将负元素从 Str 转换为 Int？ .

以下是我的分数数组；

    newArray = [['joe bloggs', '45', '46', '52', '83'],
 ['bobby uncle', '52', '45', '85', '63'],
 ['luke van', '69', '48', '45', '22'],
 ['lauren loo', '75', '24', '-65', '32'],
 ['heidi ho', '65', '7', '58', '14'],
 ['robyn cook', '23', '24', '51', '63'],
 ['cath roberts', '56', '85', '14', '74'],
 ['june jules', '58', '45', '26', '65'],
 ['dan nissie', '41', '56', '85', '45'],
 ['chris cooks', '24', '-15', '25', '75'],
 ['Kate Vander', '105', '23', '67', '1'],
 ['Luther rose', '55', '25', '207', '45']]






error = ""
for row in newArray:
    for index,col in enumerate(row):
        if col.isdigit() == True:
            if int(col)<0 or int(col)>100:
                error = error + col
                newArray.remove(row)

e.write(error)#I have a txt file set up for this. 

我也在尝试使用此代码仅删除单个元素。我读到删除一个元素会导致索引出现问题，可能不会删除元素，因此最好制作一个数组的副本，对其进行迭代，然后将其从原始数组中删除，但这会给我一个错误。

我试过了；

for row in copyOfArray:
    for col in row:
       if col.isdigit()== True:
           if int(col) < 0 or int(col) > 100:
              e.write(col)
              newArray.remove(col)

基本上结果应该是： #这个当我删除行时

newArray = [['joe bloggs', '45', '46', '52', '83'],
 ['bobby uncle', '52', '45', '85', '63'],
 ['luke van', '69', '48', '45', '22'],
 ['heidi ho', '65', '7', '58', '14'],
 ['robyn cook', '23', '24', '51', '63'],
 ['cath roberts', '56', '85', '14', '74'],
 ['june jules', '58', '45', '26', '65'],
 ['dan nissie', '41', '56', '85', '45']]

或

#this when I remove just the single element:
newArray = [['joe bloggs', '45', '46', '52', '83'],
 ['bobby uncle', '52', '45', '85', '63'],
 ['luke van', '69', '48', '45', '22'],
 ['lauren loo', '75', '24', '32'],
 ['heidi ho', '65', '7', '58', '14'],
 ['robyn cook', '23', '24', '51', '63'],
 ['cath roberts', '56', '85', '14', '74'],
 ['june jules', '58', '45', '26', '65'],
 ['dan nissie', '41', '56', '85', '45'],
 ['chris cooks', '24', '25', '75'],
 ['Kate Vander', '23', '67', '1'],
 ['Luther rose', '55', '25', '45']]

对于这个问题的规模，我深表歉意。

Answer 1

如果你想从列表中删除单个元素，你可以这样做：

newArray = [['joe bloggs', '45', '46', '52', '83'],
 ['bobby uncle', '52', '45', '85', '63'],
 ['luke van', '69', '48', '45', '22'],
 ['lauren loo', '75', '24', '-65', '32'],
 ['heidi ho', '65', '7', '58', '14'],
 ['robyn cook', '23', '24', '51', '63'],
 ['cath roberts', '56', '85', '14', '74'],
 ['june jules', '58', '45', '26', '65'],
 ['dan nissie', '41', '56', '85', '45'],
 ['chris cooks', '24', '-15', '25', '75'],
 ['Kate Vander', '105', '23', '67', '1'],
 ['Luther rose', '55', '25', '207', '45']]

new_array = []

for row in newArray:
    numbers = [x for x in row if x.isdigit()]
    numbers_keep = [row[0]] + [n for n in numbers if int(n) >= 0 and int(n) <= 100]
    new_array.append(numbers_keep)

返回：

[['joe bloggs', '45', '46', '52', '83'],
 ['bobby uncle', '52', '45', '85', '63'],
 ['luke van', '69', '48', '45', '22'],
 ['lauren loo', '75', '24', '32'],
 ['heidi ho', '65', '7', '58', '14'],
 ['robyn cook', '23', '24', '51', '63'],
 ['cath roberts', '56', '85', '14', '74'],
 ['june jules', '58', '45', '26', '65'],
 ['dan nissie', '41', '56', '85', '45'],
 ['chris cooks', '24', '25', '75'],
 ['Kate Vander', '23', '67', '1'],
 ['Luther rose', '55', '25', '45']]

如果要跟踪已删除的项目，可以在创建 numbers_keep 列表后使用以下行。我不确定您希望在将删除的项目写入文档之前如何对其进行格式化，所以我将把它留给您。

diff = set(row) ^ set(numbers_keep)