变量像类型一样使用[重复]答案

【问题标题】：variable used like a type [duplicate]变量像类型一样使用[重复]
【发布时间】：2018-07-04 19:39:14
【问题描述】：

返回语句中出现错误“'mydata' 是一个变量，但用作类型” 如何修复错误？

    [HttpGet]
    public JsonResult NewData()
    {
        List<mydatasample> mydata = new List<mydatasample>(); 
        mydata.Add(new mydatasample { bookName = "test1", publisherName = "yum3", publishYear = 2018 });
        mydata.Add(new mydatasample { bookName = "test1", publisherName = "yum3", publishYear = 2018 });
        mydata.Add(new mydatasample { bookName = "test2", publisherName = "yum3", publishYear = 2018 });
        mydata.Add(new mydatasample { bookName = "test1", publisherName = "yum3", publishYear = 2018 });
        mydata.Add(new mydatasample { bookName = "test1", publisherName = "yum3", publishYear = 2018 });
        mydata.Add(new mydatasample { bookName = "test1", publisherName = "yum3", publishYear = 2018 });
        mydata.Add(new mydatasample { bookName = "test1", publisherName = "yum3", publishYear = 2018 });
        mydata.Add(new mydatasample { bookName = "test1", publisherName = "yum3", publishYear = 2018 });
        mydata.Add(new mydatasample { bookName = "test1", publisherName = "yum3", publishYear = 2018 });
        mydata.Add(new mydatasample { bookName = "test1", publisherName = "yum3", publishYear = 2018 });



        return Json(new mydata { }, JsonRequestBehavior.AllowGet);
    }

【问题讨论】：

只是return Json(mydata, JsonRequestBehavior.AllowGet);

标签： c# asp.net-mvc

【解决方案1】：

您在 return 语句上创建另一个对象。请从返回行中删除新关键字和 {}。

[HttpGet]
public JsonResult NewData()
{
    List<mydatasample> mydata = new List<mydatasample>(); 
    mydata.Add(new mydatasample { bookName = "test1", publisherName = "yum3", publishYear = 2018 });
    mydata.Add(new mydatasample { bookName = "test1", publisherName = "yum3", publishYear = 2018 });
    mydata.Add(new mydatasample { bookName = "test2", publisherName = "yum3", publishYear = 2018 });
    mydata.Add(new mydatasample { bookName = "test1", publisherName = "yum3", publishYear = 2018 });
    mydata.Add(new mydatasample { bookName = "test1", publisherName = "yum3", publishYear = 2018 });
    mydata.Add(new mydatasample { bookName = "test1", publisherName = "yum3", publishYear = 2018 });
    mydata.Add(new mydatasample { bookName = "test1", publisherName = "yum3", publishYear = 2018 });
    mydata.Add(new mydatasample { bookName = "test1", publisherName = "yum3", publishYear = 2018 });
    mydata.Add(new mydatasample { bookName = "test1", publisherName = "yum3", publishYear = 2018 });
    mydata.Add(new mydatasample { bookName = "test1", publisherName = "yum3", publishYear = 2018 });



    return Json(mydata, JsonRequestBehavior.AllowGet);
}

【讨论】：

【解决方案2】：

正如 cmets 中所说，错误在 Return 中

   [HttpGet]
    public JsonResult NewData()
    {
        List<mydatasample> mydata = new List<mydatasample>(); 
        mydata.Add(new mydatasample { bookName = "test1", publisherName = "yum3", publishYear = 2018 });
        mydata.Add(new mydatasample { bookName = "test1", publisherName = "yum3", publishYear = 2018 });
        mydata.Add(new mydatasample { bookName = "test2", publisherName = "yum3", publishYear = 2018 });
        mydata.Add(new mydatasample { bookName = "test1", publisherName = "yum3", publishYear = 2018 });
        mydata.Add(new mydatasample { bookName = "test1", publisherName = "yum3", publishYear = 2018 });
        mydata.Add(new mydatasample { bookName = "test1", publisherName = "yum3", publishYear = 2018 });
        mydata.Add(new mydatasample { bookName = "test1", publisherName = "yum3", publishYear = 2018 });
        mydata.Add(new mydatasample { bookName = "test1", publisherName = "yum3", publishYear = 2018 });
        mydata.Add(new mydatasample { bookName = "test1", publisherName = "yum3", publishYear = 2018 });
        mydata.Add(new mydatasample { bookName = "test1", publisherName = "yum3", publishYear = 2018 });



        return Json(mydata, JsonRequestBehavior.AllowGet);
    }

【讨论】：