您可以使用一个自定义类型类来做到这一点,该类证明只有一个TB,而所有其他元素都是TA。如果您想以归纳方式构建此列表,您会发现有两种情况需要处理——到目前为止,您看到的所有内容都是 TA(我们可以通过 ToList[T, TA] 见证)和当前元素是TB,或者你已经看到了一个TB,并且当前元素是TA:
import shapeless._, ops.hlist.{ ToList }
trait T
case class TA() extends T
case class TB() extends T
trait UniqueTB[L <: HList] extends DepFn1[L] {
type Out = TB
def apply(l: L): TB
}
object UniqueTB {
def apply[L <: HList](implicit utb: UniqueTB[L]): UniqueTB[L] = utb
def getTB[L <: HList](l: L)(implicit utb: UniqueTB[L]): TB = utb(l)
implicit def firstTB[T <: HList](
implicit tl: ToList[T, TA]
): UniqueTB[TB :: T] = new UniqueTB[TB :: T] {
def apply(l: TB :: T): TB = l.head
}
implicit def afterTB[T <: HList](
implicit utb: UniqueTB[T]
): UniqueTB[TA :: T] = new UniqueTB[TA :: T] {
def apply(l: TA :: T): TB = utb(l.tail)
}
}
然后:
scala> UniqueTB[TB :: HNil]
res0: UniqueTB[shapeless.::[TB,shapeless.HNil]] = UniqueTB$$anon$1@385c6929
scala> UniqueTB[TA :: TB :: HNil]
res1: UniqueTB[shapeless.::[TA,shapeless.::[TB,shapeless.HNil]]] = UniqueTB$$anon$2@682dd97e
scala> UniqueTB[TA :: TB :: TA :: HNil]
res2: UniqueTB[shapeless.::[TA,shapeless.::[TB,shapeless.::[TA,shapeless.HNil]]]] = UniqueTB$$anon$2@5ef48f82
scala> UniqueTB[TB :: HNil]
res3: UniqueTB[shapeless.::[TB,shapeless.HNil]] = UniqueTB$$anon$1@33be241
scala> UniqueTB[TA :: HNil]
<console>:25: error: could not find implicit value for parameter utb: UniqueTB[shapeless.::[TA,shapeless.HNil]]
UniqueTB[TA :: HNil]
^
scala> UniqueTB[HNil]
<console>:25: error: could not find implicit value for parameter utb: UniqueTB[shapeless.HNil]
UniqueTB[HNil]
^
scala> UniqueTB[TB :: TB :: HNil]
<console>:25: error: could not find implicit value for parameter utb: UniqueTB[shapeless.::[TB,shapeless.::[TB,shapeless.HNil]]]
UniqueTB[TB :: TB :: HNil]
^
我已经为类型类提供了一个返回 TB 的操作,但如果你不需要它,你可以让它不使用方法。