正则表达式用“and”替换相同的单词

Question

在下面的例句中：

绿衬衫绿帽子

是否可以使用正则表达式检测2个相同的单词并将第二个替换为and成为：

绿色衬衫和帽子

---

一个更难的字符串示例。这里需要替换第一个相同的词：

你是一个有艺术天赋和音乐天赋的人

应该变成：

你是一个有艺术和音乐天赋的人

Answer 1

说明

首先，正则表达式并不是最理想的解决方案，但我相信您有使用它的理由。

((\b[a-z]{1,}\b).*?)(\b\2\b)(.*)$

替换为： \1and\4

总结

此正则表达式将在字符串中找到两个相同的单词，并将第二个单词替换为and。

示例

现场演示

https://regex101.com/r/yG3yM6/2

示例文本

Green shirt green hat
Green shirt greenish hat
You are an artistically gifted musically gifted individual

示例匹配

Green shirt and hat
Green shirt greenish hat
You are an artistically gifted musically and individual

说明

NODE                     EXPLANATION
----------------------------------------------------------------------
  (                        group and capture to \1:
----------------------------------------------------------------------
    (                        group and capture to \2:
----------------------------------------------------------------------
      \b                       the boundary between a word char (\w)
                               and something that is not a word char
----------------------------------------------------------------------
      [a-z]{1,}                any character of: 'a' to 'z' (at least
                               1 times (matching the most amount
                               possible))
----------------------------------------------------------------------
      \b                       the boundary between a word char (\w)
                               and something that is not a word char
----------------------------------------------------------------------
    )                        end of \2
----------------------------------------------------------------------
    .*?                      any character except \n (0 or more times
                             (matching the least amount possible))
----------------------------------------------------------------------
  )                        end of \1
----------------------------------------------------------------------
  (                        group and capture to \3:
----------------------------------------------------------------------
      \b                       the boundary between a word char (\w)
                               and something that is not a word char
----------------------------------------------------------------------
    \2                       what was matched by capture \2
----------------------------------------------------------------------
      \b                       the boundary between a word char (\w)
                               and something that is not a word char
----------------------------------------------------------------------
  )                        end of \3
----------------------------------------------------------------------
  (                        group and capture to \4:
----------------------------------------------------------------------
    .*                       any character except \n (0 or more times
                             (matching the most amount possible))
----------------------------------------------------------------------
  )                        end of \4
----------------------------------------------------------------------
  $                        before an optional \n, and the end of a
                           "line"
----------------------------------------------------------------------

额外积分

虽然在 OP 中没有解决，但如果有问题的单词使用非 a-z 字符，那么您可以将 [a-z] 替换为匹配非英语字符的 [a-z]|[^\x00-\x7F]。但是接下来我们需要将\b\2\b 更改为(?<=\s|^)\2(?=\s|$)，这样我们才能确保正确匹配。

((\b(?:[a-z]|[^\x00-\x7F]){1,}\b).*?)((?<=\s|^)\2(?=\s|$))(.*)$

现场演示 https://regex101.com/r/wD8yF5/2

Answer 2

修改this answer即可：

console.log( myFunc("Green shirt green hat") );
console.log( myFunc("Big red eyed rabbits red Ferrari") );

function myFunc(str) {
    return str.replace(/\b(\w+)(.+)(\1)\b/gi, "$1$2and");
}

Answer 3

您可以使用RegExp /(\bgreen\b)/ig，其中green 是要匹配的单词，String.prototype.replace()，当在替换函数中达到p2 时

p1, p2, ... nth 带括号的子匹配字符串，前提是 replace() 的第一个参数是 RegExp 对象。 （对应于 $1，$2，等等。）例如，如果给定了/(\a+)(\b+)/， p1 是 \a+ 的匹配项，p2 是 \b+ 的匹配项。

将green 替换为and

var str = "Green shirt green hat green";
var re = function(m, p1, p2, index) {
  return p2 ? "and" : m
}
str = str.replace(/(\bgreen\b)/ig, re);
console.log(str);

Answer 4

您可以使用以下内容：

/(\b([^\s]+)\b.*?)\b\2\b/gi

测试用例：

var regex = /(\b([^\s]+)\b.*?)\b\2\b/gi;
'Green shirt green hat with blue shoes blue glasses'.replace(regex, '$1and')
  === 'Green shirt and hat with blue shoes and glasses';
'Orange colored oranges orange belts'.replace(regex, '$1and')
  === 'Orange colored oranges and belts';

Try it online

Answer 5

你的第一个例子的答案 - 我读为用'and'替换第一个重复单词的第二个 - 是：

var str = 'Green shirt green hat';

str = str.replace(/(\b\S+\b)(.+?)(\b\1\b)/i, '$1$2and');

console.log(str);

你的第二个例子的答案 - 我读为用'and'替换第一个重复的单词 - 是：

var str = 'You are an artistically gifted musically gifted individual';

str = str.replace(/(\b\S+\b)(.+?)(\b\1\b)/i, 'and$2$1');

console.log(str);