验证文档是否与我发送的数据相同答案

【问题标题】：validate if documents have same data as I send验证文档是否与我发送的数据相同
【发布时间】：2021-12-31 00:29:44
【问题描述】：

我在数据库中有以下文档：（每个文档都是一个有成员的房间）

[
  {
    "id": "room1",
    "members": [{
      "id": "member1",
      "acks": "XXX",
    },{
      "id": "member2",
      "acks": "XXX",
    },{
      "id": "member3",
      "acks": "XXX",
    },{
      "id": "member4",
      "acks": "XXX",
    }]
  },
  {
    "id": "room2",
    "members": [{
      "id": "memberA",
      "acks": "XXX",
    },{
      "id": "memberB",
      "acks": "XXX",
    },{
      "id": "memberC",
      "acks": "XXX",
    },{
      "id": "memberD",
      "acks": "XXX",
    },{
      "id": "memberE",
      "acks": "XXX",
    },{
      "id": "memberF",
      "acks": "XXX",
    }]
  },
  {
    "id": "room3",
    "members": [{
      "id": "memberX",
      "acks": "XXX",
    },{
      "id": "memberY",
      "acks": "XXX",
    },{
      "id": "memberZ",
      "acks": "XXX",
    }]
  }
]

从前端发送下一个数据：

[{
  "id": "room1"
  "members": ["member1", "member2"]
},{
    "id": "room2"
  "members": ["memberA", "memberB", "memberC", "memberF"]
},{
  "id": "room3"
  "members": ["memberX", "memberY"]
}]

我想检查每个房间的所有成员是否匹配，并返回一个唯一的布尔值作为响应 --> 如果全部匹配则返回 True，如果不匹配则返回 False。

此数据应返回 false：

[{
  "id": "room1"
  "members": ["memberA", "member2"] //Because memberA is not in room1
},{
  "id": "room2"
  "members": ["memberA", "memberB", "memberC", "memberF"]
},{
  "id": "room3"
  "members": ["memberX", "memberY"]
}]

Playground

是否可以通过一个查询来实现？

非常感谢您。

【问题讨论】：

标签： mongodb mongoose

【解决方案1】：

你可以试试查询，

根据前端请求准备查询请求

// consider this is your request parameter
let request = [{
  "id": "room1",
  "members": ["member1", "member2"]
},{
    "id": "room2",
  "members": ["memberA", "memberB", "memberC", "memberF"]
},{
  "id": "room3",
  "members": ["memberX", "memberY"]
}];
// prepare query
let query = request.map((r) => {
  return { 
    id: r.id, 
    members: r.members.map((m) => {
      return { "members.id": m }
    })
  }
});
console.log(query)

尝试countDocuments 函数并获取有请求的房间总数

async function hasRooms (query) {
  let count = await Schema.countDocuments({ $or: query });
  return (count === request.length);
}

Playground

使用你的函数

console.log(await hasRooms(query));

【讨论】：