【发布时间】:2017-09-07 10:40:52
【问题描述】:
我是 Spring Boot 和 Mongo DB 的新手,我正在尝试对 POJO 类进行建模 - 'Patient' 和 'Survey' 应该存储和保留患者调查数据。调查数据将以 JSON 形式从第 3 方提供给我们,其中包含任意编号。问题和答案以及任意类型。
我应该使用什么数据类型/注释将嵌套的 JSON 存储为单个实体/对象? 我听说 Mongo DB 将 JSON 存储为 BSON。但是我该怎么做呢?
目前我的模型类看起来像这样
@Document
public class Patient {
@Id private String id;
private String pID;
private String firstName;
private String lastName;
@DBRef
private List<Survey> surveys;
public Patient() { }
public Patient(String fName, String lName)
{
this.firstName = fName;
this.lastName = lName;
}
public String getpID() {
return pID;
}
public void setpID(String pID) {
this.pID = pID;
}
public String getFirstName() {
return firstName;
}
public void setFirstName(String firstName) {
this.firstName = firstName;
}
public String getLastName() {
return lastName;
}
public void setLastName(String lastName) {
this.lastName = lastName;
}
}
@Document
public class Survey {
@Id private String id;
private String pID;
private Document surveyData;
public Survey(String pID, Document surveyData)
{
this.pID = pID;
this.surveyData = surveyData;
}
public String getpID() {
return pID;
}
public void setpID(String pID) {
this.pID = pID;
}
public Document getSurveyData() {
return surveyData;
}
public void setSurveyData(Document surveyData) {
this.surveyData = surveyData;
}
}
@RepositoryRestResource(collectionResourceRel = "Survey", path = "survey")
public interface SurveyRepository extends MongoRepository<Survey, String> {
public Survey findBypID(@Param("pID") String pID);
}
这是我用来测试的 JSON。
{
"pID": "test1",
"surveyData" : {
"resourceType": "QuestionnaireResponse",
"questionnaire": {
"reference": "http://hl7.org/fhir/2016Sep/cqif/questionnaire-cqif-example.xml.html"
},
"item": [
{
"linkId": "Q1",
"text": "Little interest or pleasure in doing things",
"answer": [
{
"valueString": "Several Days"
}
]
},
{
"linkId": "Q2",
"text": "Feeling down, depressed, or hopeless",
"answer": [
{
"valueString": "Several Days"
}
]
},
{
"linkId": "Q3",
"text": "Trouble falling or staying asleep",
"answer": [
{
"valueString": "Several Days"
}
]
},
{
"linkId": "Q4",
"text": "Feeling tired or having little energy",
"answer": [
{
"valueString": "More than half days"
}
]
},
{
"linkId": "Q5",
"text": "Poor appetite or overeating",
"answer": [
{
"valueString": "Several Days"
}
]
},
{
"linkId": "Q6",
"text": "Feeling bad about yourself - or that you are a failure or have let yourself or your family down",
"answer": [
{
"valueString": "More than half days"
}
]
},
{
"linkId": "Q7",
"text": "Trouble concentrating on things, such as reading the newspaper or watching television",
"answer": [
{
"valueString": "Several Days"
}
]
},
{
"linkId": "Q8",
"text": "Moving or speaking so slowly that other people could have noticed. Or the opposite - being so fidgety or restless that you have been moving around a lot more than usual",
"answer": [
{
"valueString": "More than half days"
}
]
},
{
"linkId": "Q9",
"text": "If you checked off any problems, how difficult have these problems made it for you to do your work, take care of things at home, or get along with other people",
"answer": [
{
"valueString": "Several Days"
}
]
}
]
}
}
我得到的例外是
2017-03-15 17:18:19.257 ERROR 15364 --- [nio-8080-exec-3] o.s.d.r.w.RepositoryRestExceptionHandler : Could not read document: Can not deserialize Class org.springframework.data.mongodb.core.mapping.Document (of type annotation) as a Bean
at [Source: org.apache.catalina.connector.CoyoteInputStream@5d3981f6; line: 1, column: 1]; nested exception is com.fasterxml.jackson.databind.JsonMappingException: Can not deserialize Class org.springframework.data.mongodb.core.mapping.Document (of type annotation) as a Bean
at [Source: org.apache.catalina.connector.CoyoteInputStream@5d3981f6; line: 1, column: 1]
【问题讨论】:
-
"... 将 JSON 存储为 GSON" - 您可能指的是 BSON,而不是 Gson - Gson 是一个库,而 BSON 是一种数据格式。这个问题似乎超出了
gson标签范围。 -
您能提供一份调查样本文件吗?
-
嗨,Markus,是的,我的意思是 BSON
标签: java json mongodb spring-data-mongodb bson