【发布时间】:2021-08-01 21:10:48
【问题描述】:
我有这样的数据库集合
[
{
name: "Fried Burger",
image: "https://burgerimage.com",
category: "burger"
},
{
name: "Fried Pizza",
image: "https://pizzaimage.com",
category: "pizza"
},
{
name: "Veg Pizza",
image: "https://vegpizzaimage.com",
category: "pizza"
},
{
name: "Fried Pasta",
image: "https://friedpastaimage.com",
category: "pasta"
}
]
有什么方法可以让我从类别中获得价值而无需重复和单个图像,尽管有多个这样的类别
[
{category: "burger", image:"https://burgerimage.com"},
{category: "pizza", image:"https://pizzaimage.com"}, //Any image works as long as category is same
{category: "pasta", image:"https://pastaimage.com"}
我使用了 .distinct('category') 但它只返回这样,但我也想要一张带有该图像的图像
{
"category": [
"Burger",
"beef",
"chicken",
"duck",
"pasta",
"pizza",
"pork"
]
}
【问题讨论】: