【发布时间】:2016-10-17 17:55:17
【问题描述】:
我正在使用 mysql 构建基于 PHP 的搜索。
但我遇到了这个问题: 我有一个很长很重(在 mysql 服务器上)的搜索查询。
要对结果进行分页,我需要以下数据:
-
所有结果的计数(不限制,所以我知道要显示多少个妈妈)
SELECT COUNT(*) as count FROM table WHERE col="val" -
有限的结果 - 我向用户展示这些
SELECT * FROM table WHERE col="val" LIMIT 20, 10
如何避免对上述 2 个要求进行 2 个单独的查询?
注意: 为了避免“您的查询有多大?”,这是我真正的 where 条件:
SELECT *,
(1000 * 6371 * acos( cos( radians(42.6051862) ) * cos( radians( project_lat ) ) * cos( radians( project_lng ) - radians(23.037836800000036) ) + sin( radians(42.6051862) ) * sin( radians( project_lat ) ) ) ) AS distance
FROM `projects`
JOIN `subcategories` ON `projects`.`subcat_id` = `subcategories`.`subcat_id`
JOIN `categories` ON `subcategories`.`cat_id` = `categories`.`cat_id`
JOIN `project_images` ON `projects`.`project_id` = `project_images`.`project_id`
WHERE `projects`.`subcat_id` = 618
AND `project_start` < '2016-10-30'
AND `project_start` > '2016-10-14'
AND `project_price` > 123
AND `project_price` < 233
AND `project_currency` = 'BTN'
AND `project_approved` = 1
AND MATCH (project_title, project_description) AGAINST ('test')
GROUP BY `projects`.`project_id`
HAVING `distance` < 7400
【问题讨论】:
标签: php mysql pagination