如何将数组中的数据映射到 Mule Dataweave 中具有不同索引的另一个数组输出答案

【问题标题】：How to map data in an array to another array output with different index in Mule Dataweave如何将数组中的数据映射到 Mule Dataweave 中具有不同索引的另一个数组输出
【发布时间】：2019-06-24 21:17:03
【问题描述】：

我有一个这样的 JSON：

{
"invoice-line": [
    {
        "id": "01",
        "date": "2019-06-21",
        "sales-date": "2019-06-21",
        "line-num": "1",
        "item": "Mouse",
        "descrption": "This is line 1 item"
    },
    {
        "id": "02",
        "date": "2019-06-21",
        "sales-date": "2019-06-21",
        "line-num": "2",
        "item": "Keyboard",
        "descrption": "This is line 2 item"
    },
    {
        "id": "03",
        "date": "2019-06-21",
        "sales-date": "2019-06-21",
        "line-num": "3",
        "item": "Monitor",
        "descrption": "This is line 3 item"
    }
]
}

我们需要从这个输入 JSON 中提取数据并映射到另一个输出 JSON，但需要遵循以下逻辑：
当 line-num = 1 然后映射 id、日期、销售日期、描述然后休息或数组将映射 id, item, descrption
如下所示：

{
"row": [
    {
        "id": "01",
        "date": "2019-06-21",
        "sales-date": "2019-06-21",
        "line-num": "1",
        "item": "",
        "descrption": "This is line 1 item"
    },
    {
        "id": "02",
        "date": "",
        "sales-date": "",
        "line-num": "",
        "item": "Mouse",
        "descrption": "This is line 2 item"
    },
    {
        "id": "03",
        "date": "",
        "sales-date": "",
        "line-num": "",
        "item": "Monitor",
        "descrption": "This is line 3 item"
    }
]
}

还可以执行诸如将数组项（第一个索引）映射到不同的输出数组之类的操作吗？例如：

{
"row": [
    {
        "id": "",
        "date": "2019-06-21",
        "sales-date": "2019-06-21",
        "line-num": "1",
        "item": "",
        "descrption": ""
    },
    {
        "id": "01",
        "date": "",
        "sales-date": "",
        "line-num": "",
        "item": "Keyboard",
        "descrption": "This is line 1 item"
    },
    {
        "id": "02",
        "date": "",
        "sales-date": "",
        "line-num": "",
        "item": "Mouse",
        "descrption": "This is line 2 item"
    },
    {
        "id": "03",
        "date": "",
        "sales-date": "",
        "line-num": "",
        "item": "Monitor",
        "descrption": "This is line 3 item"
    }
]
}

【问题讨论】：

标签： mule dataweave

【解决方案1】：

希望这是您要找的：

%dw 1.0
%output application/json
---
row: 
    (payload.invoice-line filter ($.line-num == '1') map {
            id: "",
            date: $.date,
            sales-date: $.sales-date,
            line-num: $.line-num,
            item: "",
            descrption: ""
        })
    ++
    (payload.invoice-line map {
            id: $.id,
            date: "",
            sales-date: "",
            line-num: "",
            item: $.item,
            descrption: $.descrption
    })

产生：

{
    "row": [
        {
            "id": "",
            "date": "2019-06-21",
            "sales-date": "2019-06-21",
            "line-num": "1",
            "item": "",
            "descrption": ""
        },
        {
            "id": "01",
            "date": "",
            "sales-date": "",
            "line-num": "",
            "item": "Mouse",
            "descrption": "This is line 1 item"
        },
        {
            "id": "02",
            "date": "",
            "sales-date": "",
            "line-num": "",
            "item": "Keyboard",
            "descrption": "This is line 2 item"
        },
        {
            "id": "03",
            "date": "",
            "sales-date": "",
            "line-num": "",
            "item": "Monitor",
            "descrption": "This is line 3 item"
        }
    ]
}

【讨论】：

非常感谢，但是是的，这不是我想要的，因为输出字段（发布目标）无法从我这边控制，所以我无法在该行数组上添加标题或行
不用担心。明天早上我可以为您提供预期的输出
谢谢，这对我帮助很大...仍在寻找将两种不同逻辑应用于一个数组的方法...
希望新版本更好。如果是，请将答案标记为正确。谢谢！
这看起来很棒。感谢您的帮助！