反应原生 jwt auth 基本 api

Question

他们给我的信息是 API 已经在服务器上 我只能使请求类型为 GET 并且需要不同的参数登录端点需要参数“数据” 带有这些值 {"user": "juan", "userid": "123", "passw": "000"}

我需要知道如何使用我只能发出 GET 请求并需要来自 React Native 的参数的 API 登录（） {

fetch (Api/a/login',{
    method: "GET",
    headers: {
    'Content-Type': 'application/json',
        Accept: 'application/json',
        Authorization', 'Basic ' + "here should go a token or parameters"
    //'Authorization', 'Basic ' + base64.encode(this.state.user+ ":" + this.state.userid+ ":" + this.state.password)
    }
body: JSON.stringify({   // I don't know if I need you to wear this "body"
        user: this.state.user,
    userid: this.state.userid,
        password: this.state.password
  }),
}).then((response) => response.json())
  .then((responseData) =>{
      console.log("LoginData:-" + JSON.stringify(responseData));
   }).done();
}

Answer 1

你可以这样做：

const username = "julian";
const userid = 123;
const passw = "000";

fetch (`Api/a/login?user=${username}&userid=${userid}&password=${passw}`,{
    method: "GET",
    headers: {
    'Content-Type': 'application/json',
        Accept: 'application/json',
        Authorization', 'Basic ' + "here should go a token or parameters"
    //'Authorization', 'Basic ' + base64.encode(this.state.user+ ":" + this.state.userid+ ":" + this.state.password)
    }
}).then((response) => response.json())
  .then((responseData) =>{
      console.log("LoginData:-" + JSON.stringify(responseData));
   }).done();
}

在 URL 中传递参数时，您可以删除正文。