【发布时间】:2016-02-15 08:11:52
【问题描述】:
我已经集成了 QuickBlox iOS sdk v2.5。我正在向特定对象发送消息,它们被发送到服务器,但用于接收消息 - (void)chatDidReceiveMessage:(QBChatMessage *)消息没有被调用
这就是我正在做的连接
[[QBChat instance] addDelegate:self];
QBUser *chatUser=[QBUser new];
chatUser.ID=[[[NSUserDefaults standardUserDefaults] objectForKey:USERID] integerValue];
chatUser.password=[[NSUserDefaults standardUserDefaults] objectForKey:PASSWORD];
[[QBChat instance] connectWithUser:chatUser completion:nil];
用于创建聊天对话框
QBChatDialog *chatDialog=[[QBChatDialog alloc] initWithDialogID:NULL type:QBChatDialogTypePrivate];
chatDialog.name = @"Chat with Garry";
NSMutableArray *chatPartners=[[NSMutableArray alloc] initWithObjects:[chatPartner objectForKey:@"id"] ,[[NSUserDefaults standardUserDefaults] objectForKey:USERID], nil];
chatDialog.occupantIDs=chatPartners;
[QBRequest createDialog:chatDialog successBlock:^(QBResponse *response, QBChatDialog *createdDialog) {
//Success
NSDictionary* json = [NSJSONSerialization JSONObjectWithData:response.data options:kNilOptions error:nil];
[[NSUserDefaults standardUserDefaults] setObject:[json object
} errorBlock:^(QBResponse *response) {
//error
}];
然后发送消息
QBChatMessage *message =[QBChatMessage message];
[message setText:self.messageText.text];
params[@"messageStatus"]=@"Test Message";
params[@"save_to_history"] = @YES;
[message setCustomParameters:params];
[message setRecipientID:[[[NSUserDefaults standardUserDefaults] objectForKey:PARTNERID] integerValue]]; //
[QBRequest createMessage:message successBlock:^(QBResponse *response, QBChatMessage *createdMessage) {
self.messageText.text = @"Type Here...";
[self addMessagetoChat:createdMessage];
NSLog(@"success: %@", createdMessage);
} errorBlock:^(QBResponse *response) {
self.messageText.text = @"Type Here...";
NSLog(@"ERROR: %@", response.error);
}];
消息已发送到聊天室,但其他用户无法接收。- (void)chatDidReceiveMessage:(QBChatMessage *) 未调用消息。或者可能是我使用了错误的功能。
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标签: ios objective-c chat quickblox xmppframework