【问题标题】:Trouble creating xmpp muc room: Code 503 (service unavailable)无法创建 xmpp muc 房间:代码 503(服务不可用)
【发布时间】:2012-08-01 05:23:40
【问题描述】:

我创建房间的代码:

XMPPRoomCoreDataStorage *rosterstorage = [[XMPPRoomCoreDataStorage alloc] init];
XMPPRoom *xmppRoom = [[XMPPRoom alloc] initWithRoomStorage:rosterstorage jid:[XMPPJID jidWithString:@"groupchat@xmpp.getkismet.com/groupchat"] dispatchQueue:dispatch_get_main_queue()];

[xmppRoom activate:[[self appDelegate] xmppStream]];
if ([xmppRoom preJoinWithNickname:@"nameToCreateRoom"]) 
{
    NSLog(@"room created");
    [xmppRoom joinRoomUsingNickname:self.userName history:nil];
}
[xmppRoom fetchConfigurationForm];
[xmppRoom configureRoomUsingOptions:nil];
[xmppRoom addDelegate:[self appDelegate] delegateQueue:dispatch_get_main_queue()];

调试:

2012-08-03 07:46:29.204 iPhoneXMPP[9887:fb03] room created
2012-08-03 07:46:29:230 iPhoneXMPP[9887:15003] SEND: <iq type="get" to="groupchat@xmpp.getkismet.com" id="B793062B-0E09-492F-BC0F-703503AAA664"><query xmlns="http://jabber.org/protocol/muc#owner"/></iq>
2012-08-03 07:46:29:237 iPhoneXMPP[9887:15003] SEND: <iq type="set" to="groupchat@xmpp.getkismet.com" id="392D5BFC-707B-4F68-A829-56F949F4E96D"><query xmlns="http://jabber.org/protocol/muc#owner"><x xmlns="jabber:x:data" type="submit"/></query></iq>
2012-08-03 07:46:29:326 iPhoneXMPP[9887:14f03] SEND: <presence to="groupchat@xmpp.getkismet.com"><x xmlns="http://jabber.org/protocol/muc"/><x xmlns="vcard-temp:x:update"><photo>91217a961321f8f6380ea2feefd0632353ad296c</photo></x><c xmlns="http://jabber.org/protocol/caps" hash="sha-1" node="http://code.google.com/p/xmppframework" ver="VyOFcFX6+YNmKssVXSBKGFP0BS4="/></presence>
2012-08-03 07:46:29:327 iPhoneXMPP[9887:14f03] RECV: <iq xmlns="jabber:client" from="groupchat@xmpp.getkismet.com" to="lee@xmpp.getkismet.com/41068195801343976386548353" type="error" id="B793062B-0E09-492F-BC0F-703503AAA664"><query xmlns="http://jabber.org/protocol/muc#owner"/><error code="503" type="cancel"><service-unavailable xmlns="urn:ietf:params:xml:ns:xmpp-stanzas"/></error></iq>
2012-08-03 07:46:29:343 iPhoneXMPP[9887:fb03] iPhoneXMPPAppDelegate: xmppStream:didReceiveIQ:
2012-08-03 07:46:29:421 iPhoneXMPP[9887:15003] RECV: <iq xmlns="jabber:client" from="groupchat@xmpp.getkismet.com" to="lee@xmpp.getkismet.com/41068195801343976386548353" type="error" id="392D5BFC-707B-4F68-A829-56F949F4E96D"><query xmlns="http://jabber.org/protocol/muc#owner"><x xmlns="jabber:x:data" type="submit"/></query><error code="503" type="cancel"><service-unavailable xmlns="urn:ietf:params:xml:ns:xmpp-stanzas"/></error></iq>
2012-08-03 07:46:29:440 iPhoneXMPP[9887:fb03] iPhoneXMPPAppDelegate: xmppStream:didReceiveIQ:

我看到它正在创建/加入 groupchat@xmpp.getkismet.com 而不是我指定的 groupchat@xmpp.getkismet.com/groupchat。我读到这很可能是问题所在。但是,我已经指定了完整的 jid,所以我迷路了。

提前感谢所有提供帮助的人。

【问题讨论】:

    标签: ios xcode ios5 xmpp xmppframework


    【解决方案1】:

    首先,看这里XEP-0045: Multi-User Chat
    如您所见,首先您必须发现您的用户 (XMPPJID) 在 Jabber 服务器上具有哪些功能。

    要执行此操作,请发送 next命令到您的 Jabber 服务器:

    <iq from='user@jabber.server.com/resource' id='some_expression' to='jabber.server.com' type='get'>
        <query xmlns='http://jabber.org/protocol/disco#items'/>
    </iq>
    

    或使用 XMPP 库函数在 Objective-C 中编写:

    NSError *error = nil;
    NSXMLElement *query = [[NSXMLElement alloc] initWithXMLString:@"<query xmlns='http://jabber.org/protocol/disco#items'/>" 
                                                            error:&error];
    XMPPIQ *iq = [XMPPIQ iqWithType:@"get" 
                                 to:[XMPPJID jidWithString:@"jabber.server.com"] 
                          elementID:[xmppStream generateUUID] child:query];
    [xmppStream sendElement:iq];
    

    现在在 XMPPStream 委托 - (BOOL)xmppStream:(XMPPStream *)sender didReceiveIQ:(XMPPIQ *)iq 中监听来自服务器的响应,服务器响应应该是这样的:

    <iq from='jabber.server.com' id='some_expression' to='user@jabber.server.com/resource' type='result'>
        <query xmlns='http://jabber.org/protocol/disco#items'>
            <item jid='im.jabber.server.com' name='Instant Message Service'/>
            <item jid='conference.jabber.server.com' name='Chatroom Service'/>
        </query>
    </iq>
    

    或目标c:

    - (BOOL)xmppStream:(XMPPStream *)sender didReceiveIQ:(XMPPIQ *)iq
    {
    
        if([iq isResultIQ])
        {
            if([iq elementForName:@"query" xmlns:@"http://jabber.org/protocol/disco#items"])
            {
                NSLog(@"Jabber Server's Capabilities: %@", [iq XMLString]);
            }
        }
    }
    

    现在,对于返回的每个项目,将 IQ 发送到您的服务器以获取其属性,并确定哪一个是 会议 类型,如下所示:

    <iq from='user@jabber.server.com/resource' id='some_expression' to='conference.jabber.server.com' type='get'>
        <query xmlns='http://jabber.org/protocol/disco#info'/>
    </iq>
    

    或在目标c中:

    - (BOOL)xmppStream:(XMPPStream *)sender didReceiveIQ:(XMPPIQ *)iq
    {
    
        if([iq isResultIQ])
        {
            if([iq elementForName:@"query" xmlns:@"http://jabber.org/protocol/disco#items"])
            {
                NSXMLElement *query = [iq childElement];
                NSArray *items = [query children];
                for(NSXMLElement *item in items)
                {
                    NSError *error = nil;
                    NSXMLElement *sendQuery = [[NSXMLElement alloc] initWithXMLString:@"<query xmlns='http://jabber.org/protocol/disco#info'/>" 
                                                                                error:&error];
                    XMPPIQ *sendIQ = [XMPPIQ iqWithType:@"get" 
                                                     to:[XMPPJID jidWithString:[item attributeStringValueForName:@"jid"]] 
                                              elementID:[xmppStream generateUUID] 
                                                  child:sendQuery];
                    [xmppStream sendElement:sendIQ];
                }
            }
        }
    }
    

    监听来自服务器的响应:

    <iq from='conference.jabber.server.com' id='some_expression' to='user@jabber.server.com/resource' type='result'>
        <query xmlns='http://jabber.org/protocol/disco#info'>
            <identity category='conference' name='Server Group Chat Service' type='text'/>
            <feature var='http://jabber.org/protocol/muc'/>
        </query>
    </iq>
    

    并从category:conference的身份中获取群聊域

    - (BOOL)xmppStream:(XMPPStream *)sender didReceiveIQ:(XMPPIQ *)iq
    {
    
        if([iq isResultIQ])
        {
            if([iq elementForName:@"query" xmlns:@"http://jabber.org/protocol/disco#items"])
            {
                ...
            }
            else if([iq elementForName:@"query" xmlns:@"http://jabber.org/protocol/disco#info"])
            {
                NSXMLElement *query = [iq childElement];
                NSXMLElement *identity = [query elementForName:@"identity"];
                if([[identity attributeStringValueForName:@"category"] isEqualToString:@"conference"])
                {
                    groupChatDomain = [iq fromStr];
                }
            }
        }
    }
    

    最后,当我们得到群​​聊域后,我们可以像这样创建聊天室:

    XMPPJID *chatRoomJID = [XMPPJID jidWithUser:@"chat_room" 
                                         domain:groupChatDomain 
                                       resource:@"user"];
    XMPPRoomMemoryStorage *roomMemoryStorage = [[XMPPRoomMemoryStorage alloc] init];
    XMPPRoom *xmppRoom = [[XMPPRoom alloc] initWithRoomStorage:roomMemoryStorage
                                                           jid:roomChatJID
                                                 dispatchQueue:dispatch_get_main_queue()];
    [xmppRoom activate:xmppStream];
    [xmppRoom addDelegate:self delegateQueue:dispatch_get_main_queue()];
    [xmppRoom joinRoomUsingNickname:user history:nil];
    

    并在您的视图控制器及其委托中添加&lt;XMPPRoomDelegate&gt; 协议:

    - (void)xmppRoomDidCreate:(XMPPRoom *)sender
    - (void)xmppRoomDidDestroy:(XMPPRoom *)sender
    - (void)xmppRoom:(XMPPRoom *)sender didConfigure:(XMPPIQ *)iqResult
    - (void)xmppRoom:(XMPPRoom *)sender didNotConfigure:(XMPPIQ *)iqResult
    - (void)xmppRoomDidJoin:(XMPPRoom *)sender
    - (void)xmppRoomDidLeave:(XMPPRoom *)sender
    - (void)xmppRoom:(XMPPRoom *)sender occupantDidJoin:(XMPPJID *)occupantJID withPresence:(XMPPPresence *)presence
    - (void)xmppRoom:(XMPPRoom *)sender occupantDidLeave:(XMPPJID *)occupantJID withPresence:(XMPPPresence *)presence
    - (void)xmppRoom:(XMPPRoom *)sender didReceiveMessage:(XMPPMessage *)message fromOccupant:(XMPPJID *)occupantJID
    

    注意:在邀请其他用户加入聊天室之前,您必须发送并确认房间配置(可以邀请其他用户,但不能发送消息)。
    因此,您可以在创建 Room(调用代理 - (void)xmppRoomDidCreate:(XMPPRoom *)sender)或您的用户已加入(调用代理 - (void)xmppRoomDidJoin:(XMPPRoom *)sender)到聊天室后执行此操作。

    要发送和确认房间配置,请执行以下操作之一:

    - (void)xmppRoomDidCreate:(XMPPRoom *)sender
    {
        [sender configureRoomUsingOptions:nil];
    }
    

    - (void)xmppRoomDidJoin:(XMPPRoom *)sender
    {    
        [sender configureRoomUsingOptions:nil];
    }
    

    发送nil 以接受默认选项,或者您可以使用以下语法将 IQ 发送到您的服务器:

    <iq type='set' from='user@jabber.server.com/resource' id='some_expression' to='chat_room@conference.jabber.server.com'>
        <query xmlns='http://jabber.org/protocol/muc#owner'>
            <x xmlns='jabber:x:data' type='submit'>
                <field var='FORM_TYPE'>
                    <value>http://jabber.org/protocol/muc#roomconfig</value>
                </field>
                <field var='muc#roomconfig_roomname'>
                    <value>My Chat Room</value>
                </field>
                  .
                  .
                  .
            <x>
    </query>
    </iq>
    

    或目标c代码:

    NSError *error = nil;
    NSXMLElement *query = [[NSXMLElement alloc] initWithXMLString:@"<query xmlns='http://jabber.org/protocol/muc#owner'/>" 
                                                            error:&error];
    NSXMLElement *x = [NSXMLElement elementWithName:@"x" 
                                              xmlns:@"jabber:x:data"];
    [x addAttributeWithName:@"type" stringValue:@"submit"];
    NSXMLElement *field1 = [NSXMLElement elementWithName:@"field"];
    [field1 addAttributeWithName:@"var" stringValue:@"FORM_TYPE"];
    NSXMLElement *value1 = [NSXMLElement elementWithName:@"value" 
                                             stringValue:@"http://jabber.org/protocol/muc#roomconfig"];
    [field1 addChild:value1];
    
    NSXMLElement *field2 = [NSXMLElement elementWithName:@"field"];
    [field2 addAttributeWithName:@"var" stringValue:@"muc#roomconfig_roomname"];
    NSXMLElement *value2 = [NSXMLElement elementWithName:@"value" 
                                             stringValue:@"My Chat Room"];
    [field2 addChild:value2];
    
    //Add other fields you need, just like field1 and field2
    
    [x addChild:field1];
    [x addChild:field2];
    
    [query addChild:x];
    
    NSXMLElement *roomOptions = [NSXMLElement elementWithName:@"iq"];
    [roomOptions addAttributeWithName:@"type" stringValue:@"set"];
    [roomOptions addAttributeWithName:@"id" stringValue:[xmppStream generateUUID];
    [roomOptions addAttributeWithName:@"to" stringValue:@"chat_room@conference.jabber.server.com"];
    
    [roomOptions addChild:query];
    
    [sender configureRoomUsingOptions:roomOptions];
    

    所有可能的配置表单字段的列表是here

    【讨论】:

    • 谢谢西哈德。这是一篇非常详细且有用的帖子!
    • 嗨 Sihad,感谢您提供详细的代码!我有几个问题,我一直在尝试创建一个 xmpproom,但我的 xmpproom 代表由于某种原因没有被解雇,我在这里有我的代码stackoverflow.com/questions/20765641/…
    • 在你的视图控制器 .h 文件中你是否添加了 ,它应该是这样的:@interface YourViewController : UIViewController <... xmpproomdelegate>
    • 您好,我已成功实施房间,但不知何故有以下问题。可能是我正在寻找类似whatsapp的解决方案。 1)用户不打开应用程序仍然如何让他们添加到组并发送推送通知,如创建者将您添加到组 2)即使用户不打开应用程序,消息也会在用户添加时开始发送 3 )离线消息发送给所有离开组但仍链接到组的用户 4)如何退出组和离开组与退出相同,但获取成员列表仍然给该用户。
    • 5) 无法在服务器上自动接受用户的邀请,因为应该发送需要可用状态的用户,但这会刷新存储在服务器中的所有离线消息,从而丢失他的数据。对于我的应用程序中遗留的这些问题,我们非常感谢您提供任何帮助。
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