【发布时间】:2014-09-19 12:06:06
【问题描述】:
我正在尝试过滤 eJabberd 中的消息。我收到类型为 service 的消息,对其进行处理,然后将其删除。
我的方法:我只是将返回数据包设置为<query xmlns="urn:xmpp:receipts"><query>。有没有更好的丢包方式?
on_filter_packet({From, To, XML} = Packet) ->
?INFO_MSG("on_beanstalkd ~p~n", [Packet]),
Type = xml:get_tag_attr_s(<<"type">>, XML),
DataTag = xml:get_subtag(XML, <<"data">>),
case Type =:= <<"service">> of
true ->
JSON = xml:get_tag_cdata(xml:get_subtag(XML, <<"body">>)),
{inserted, ID} = beanstalk:put(BeanstalkdPid, JSON),
Return = #xmlel{name = <<"query">>, attrs = [{<<"xmlns">>, <<"urn:xmpp:receipts">>}]};
false ->
Return = Packet
end,
Return.
【问题讨论】: