Firebase 和 Angular - 检索和显示展平数据

Question

我使用以下代码在我的 Firebase 中展平数据。但是当我想用 ng-repeat 显示最喜欢的用户帖子列表时，模板会重复第二次并且完全空白。我该如何纠正这个问题？

  "Post": {
    "xKkdfjjfld856i": {
      "name": "My first post",
      "author": "Miguel"
    },
    "xKkdfjj556FGHh": { ... },
    "xK499DF6FlHjih": { ... }
  },
  "users": {

    "John": {
      favorited_posts {
         "xKkdfjjfld856i": true,
         "xKkdfjj556FGHh": true
      }
    },
    "Mia": { ... },
    "Patrick": { ... }
  },

HTML：

<div ng-repeat="post in favoritedPosts track by $index">
    <div class="card post-card">
       <h1>{{post.name}}</h1>
       <p>{{post.author}}</p>
    </div> 
</div>

控制器：

var userRef = new Firebase("https://myApp.firebaseio.com/users")
var userFavoriteRef = userRef.child($scope.user_id).child("favorited_posts")
var favoritedPosts = $firebaseArray(userFavoriteRef)

userFavoriteRef.once("value", function(snapshot) {

  snapshot.forEach(function(childSnapshot) {

    var key = childSnapshot.key();

    var postRef = new Firebase("https://myApp.firebaseio.com/Posts")

    postRef.child(childSnapshot.ref().key()).once('value', function(postSnapshot) {
      console.log("Look",postSnapshot.val());
      $scope.favoritedPosts = postSnapshot.val();
    });

  });
});

Answer 1

尝试使用$firebaseArray 和$getRecord (documentation) 根据对象键获取对象值。然后，您将拥有所需的一切，而无需循环异步调用。

控制器

var userRef = new Firebase("https://myApp.firebaseio.com/users")
var userFavoriteRef = userRef.child($scope.user_id).child("favorited_posts")
$scope.favoritedPosts = $firebaseArray(userFavoriteRef)
var postRef = new Firebase("https://myApp.firebaseio.com/Posts")
$scope.posts = $firebaseArray(postRef)

HTML

<div ng-repeat="post in favoritedPosts">
        <div class="card post-card">
            <h1>{{posts.$getRecord(post.$id).name}}</h1>
            <p>{{posts.$getRecord(post.$id).author}}</p>
        </div> 
</div>