删除时触发 Firebase

【问题标题】：Firebase trigger on delete删除时触发 Firebase
【发布时间】：2020-05-03 23:59:07
【问题描述】：

我正在尝试创建一个可以识别谁删除的功能，问题是我没有从 firebase 服务器得到任何答案，有人可以帮助我吗？谢谢

exports.deleteFunction = functions.database.ref('/clientes')
.onDelete((context) => {
  // Grab the current value of what was written to the Realtime Database.
  console.log("delete");
  console.log(context);
});

这是要删除的函数

confirm = (e) => {
 if (id_deleta) {
      firebaseDatabase.ref('/clientes/categorias/').child(id_deleta)
            .remove();
      notification('success', 'Excluido com sucesso');
      this.callCategoria();
  } else {
    notification('error', 'Ocorreu um erro, tente mais tarde');
  }
}

【问题讨论】：

标签： firebase firebase-realtime-database google-cloud-functions

【解决方案1】：

代码修正

onDelete 事件处理程序是 defined as

function(non-null functions.database.DataSnapshot, optional non-null functions.EventContext)

所以在上面的代码中，.onDelete((context) => { 应该是 .onDelete((snapshot, context) => {。

获取删除的ID

接下来，如果你想从onDelete事件中获取id_deleta的值，你可以使用var id_deleta = snapshot.key。

exports.deleteFunction = functions.database.ref('/clientes')
.onDelete((snapshot, context) => {
  var id_deleta = snapshot.key;
  console.log("deleted ID %s", id_deleta); // logs "deleted ID 1234", etc.
  console.log(snapshot.val()); // logs the deleted data, no need for this
  console.log(context); // logs the event context
});

【讨论】：