【发布时间】:2018-01-03 13:37:40
【问题描述】:
我正在尝试在我设置的 Firebase 数据库中获取一个值,但我在尝试将其取出时遇到了问题。在我的程序中有一个部分,我在其中遍历Cities 下的每个孩子并获得每个城市的名称。我认为尝试在同一部分中获取每个城市的状态是个好主意,但我无法将其取出。下面是 JSON 对象的示例。我觉得我很接近,但缺少一些东西来把它们放在一起。
"Users" : {
"NPNBig20BXNpX4Rz0UbMyiKAarY2" : {
"Cities" : {
"New York City" : {
"Status" : "Empty"
},
"Atlanta" : {
"Status" : "Empty"
},
"Test City" : {
"Status" : "Wow",
"Value" : "Test"
}
},
"Email" : "fakeemail@gmail.com"
}
}
代码:
guard let uid = userID else { return }
let databaseRef = Database.database().reference(fromURL: "https://testApp.firebaseio.com/").child("Users").child(uid).child("Cities")
var dataTest : [String] = []
//var cityDictionary: [String:String]()
databaseRef.observeSingleEvent(of: .value, with: {(snapshot) in
for child in snapshot.children {
let snap = child as! DataSnapshot
let key = snap.key
guard let value = snap.value else { return }
//let testData = value["Status"] **Type Any has no subscript
print("Key: ", key, "\nValue: ", value)
dataTest.append(key)
}
completion(dataTest)
})
这是打印输出
Key: New York City
Value: {
Status = Empty;
}
Key: Sintra
Value: {
Status = Empty;
}
Key: Test City
Value: {
Status = Wow;
Value = Test;
}
【问题讨论】:
-
print("Key: ", key, "\nValue: ", value)打印什么? -
@RichieRich 添加了打印出来的问题
标签: swift firebase firebase-realtime-database