【问题标题】:Store multiple nodes to Firebase Realtime Database将多个节点存储到 Firebase 实时数据库
【发布时间】:2020-04-11 04:36:18
【问题描述】:

我是使用 Firebase 和 Android Studio 的新手,我需要多个节点才能从我的 Android 应用保存到 Firebase 中的实时数据库,其中包括用户、预算和支出,因为它是一个费用跟踪应用。我已经将用户信息保存在它自己的节点下,但我不知道如何为预算和支出创建节点。下面的代码是我遇到的困难:

 @Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_categories);
    setupUIViews();
    firebaseAuth = getInstance();
    mDatabase = FirebaseDatabase.getInstance().getReference();

    btn_subCat.setOnClickListener(new View.OnClickListener() {
        @Override
        public void onClick(View v) {
            if(validate()){
                sendUserBudgets();
                Toast.makeText(Categories.this, "Completed!", Toast.LENGTH_LONG).show();
                finish();
                startActivity(new Intent(Categories.this, Menu.class ));
            }else{
                Toast.makeText(Categories.this, "Submission failed", Toast.LENGTH_LONG).show();
            }
        }
    });
}
private void setupUIViews() {
    travel_input = (EditText)findViewById(R.id.travel_input);
    entertainment_input = (EditText)findViewById(R.id.entertainment_input);
    fitness_input = (EditText)findViewById(R.id.fitness_input);
    beauty_input = (EditText)findViewById(R.id.beauty_input);
    clothes_input = (EditText)findViewById(R.id.clothes_input);
    holiday_input = (EditText)findViewById(R.id.holiday_input);
    food_input = (EditText)findViewById(R.id.food_input);
    mobile_input = (EditText)findViewById(R.id.mobile_input);
    btn_subCat = (Button)findViewById(R.id.btn_subCat);

}

private Boolean validate() {
    boolean result = false;
    travel_budget = Double.parseDouble(travel_input.getText().toString().trim());
    entertainment_budget = Double.parseDouble(entertainment_input.getText().toString().trim());
    fitness_budget = Double.parseDouble(fitness_input.getText().toString().trim());
    beauty_budget = Double.parseDouble(beauty_input.getText().toString().trim());
    clothes_budget = Double.parseDouble(clothes_input.getText().toString().trim());
    holiday_budget = Double.parseDouble(holiday_input.getText().toString().trim());
    food_budget = Double.parseDouble(food_input.getText().toString().trim());
    mobile_budget = Double.parseDouble(mobile_input.getText().toString().trim());

    if(travel_budget.equals(null) || entertainment_budget.equals(null) || fitness_budget.equals(null) || beauty_budget.equals(null) || clothes_budget.equals(null) || holiday_budget.equals(null) || food_budget.equals(null) ||
            mobile_budget.equals(null)){
        Toast.makeText(Categories.this, "Please enter all fields", Toast.LENGTH_LONG).show();
    } else {
        result = true;
    }
    return result;
}

private void sendUserBudgets() {
    String currentUserID = firebaseAuth.getUid();
    CategoriesDB catDb = new CategoriesDB(travel_budget, entertainment_budget, fitness_budget, beauty_budget, clothes_budget, holiday_budget, food_budget, mobile_budget);
    mDatabase.child("User").child(currentUserID).child("Budgets").setValue(catDb);
}

【问题讨论】:

  • 运行此代码时什么不起作用?具体来说:当您在调试器中单步执行此代码时,哪一行没有按照您的预期执行?
  • 登录以查看 getUid() 返回的 currentUserID 是否确实存在于您的数据库中。
  • 这段代码中到底有什么不符合您的预期?
  • 我认为 OnClickListener 存在问题,验证不起作用,并且信息未存储在 Firebase 中的新节点下,但感谢您的帮助!我检查了日志,Firebase 的唯一 ID 已存储在数据库中! :)

标签: java android firebase firebase-realtime-database


【解决方案1】:
private void validate() {
    boolean result = false;
    travel_budget = Double.parseDouble(travel_input.getText().toString().trim());
    entertainment_budget = Double.parseDouble(entertainment_input.getText().toString().trim());
    fitness_budget = Double.parseDouble(fitness_input.getText().toString().trim());
    beauty_budget = Double.parseDouble(beauty_input.getText().toString().trim());
    clothes_budget = Double.parseDouble(clothes_input.getText().toString().trim());
    holiday_budget = Double.parseDouble(holiday_input.getText().toString().trim());
    food_budget = Double.parseDouble(food_input.getText().toString().trim());
    mobile_budget = Double.parseDouble(mobile_input.getText().toString().trim());

    if(travel_budget.equals(null) || entertainment_budget.equals(null) || fitness_budget.equals(null) || beauty_budget.equals(null) || clothes_budget.equals(null) || holiday_budget.equals(null) || food_budget.equals(null) ||
            mobile_budget.equals(null)){
        Toast.makeText(Categories.this, "Please enter all fields", Toast.LENGTH_LONG).show();
    } else {
        sendUserBudgets(travel_budget, fitness_budget, beauty_budget, clothes_budget, holiday_budget, food_budget, mobile_budget);
    }
}

private void sendUserBudgets(double travel_budget, double fitness_budget, double beauty_budget, double clothes_budget, double holiday_budget, doublefood_budget, double mobile_budget) {
    String currentUserID = firebaseAuth.getUid();
    CategoriesDB catDb = new CategoriesDB(travel_budget, entertainment_budget, fitness_budget, beauty_budget, clothes_budget, holiday_budget, food_budget, mobile_budget);
    mDatabase.child("User").child(currentUserID).child("Budgets").setValue(catDb);
}

这里一旦你获得了所有的用户输入并完成了所有的验证,你需要调用函数sendUserBudgets()将它保存到数据库中。

【讨论】:

  • 我仍然无法让它工作,我认为 OnClickListener 有问题!谢谢您的帮助! :)
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