【发布时间】:2018-06-08 19:28:03
【问题描述】:
这是我的第一个 API,我可以在我的 xyz 数据库的 abc 表中存储 id、名称、描述、价格、category_id。我只想将 image_id、image_name、image_url 也存储在同一个表中。我也想要,该图像将存储在我的上传目录中。下面,在我的代码中,我可以在我的表中存储 id、name、description、price、category_id。我为此使用 POSTMAN。谁能帮帮我.....
<?php
// required headers
header("Access-Control-Allow-Origin: *");
header("Content-Type: application/json; charset=UTF-8");
header("Access-Control-Allow-Methods: POST");
header("Access-Control-Max-Age: 3600");
header("Access-Control-Allow-Headers: Content-Type, Access-Control-Allow-Headers, Authorization, X-Requested-With");
// get database connection
include_once '../config/database.php';
// instantiate product object
include_once '../objects/product.php';
$database = new Database();
$db = $database->getConnection();
$product = new Product($db);
// get posted data
$data = (object) $_POST;
// set product property values
$product->name = $data->name;
$product->price = $data->price;
$product->description = $data->description;
$product->category_id = $data->category_id;
$product->created = date('Y-m-d H:i:s');
// create the product
if($product->create()){
echo '{';
echo '"message": "Product was created."';
echo '}';
}
// if unable to create the product, tell the user
else{
echo '{';
echo '"message": "Unable to create product."';
echo '}';
}
?>
【问题讨论】: