PostgreSql：将行插入数据库后无法检索行？

Question

CREATE OR REPLACE FUNCTION sp_post_items(i_data json)
 RETURNS table (fulfiller_id character varying,item_id character varying, order_id character varying, 
 status_id integer, 
-- sku_code character varying, decoration_technology character varying, quantity integer,  
 item_updated_time timestamp without time zone)

AS $function$
begin

 insert into vw_item_status_detail (fulfiller_id ,item_id ,order_id , status_id , sku_code ,
 decoration_technology ,quantity, item_updated_time)
 select 
    i_data->>'fulfillerId', 
    t->>'itemId', 
    i_data->>'orderId', 
    1000,
    t->>'skuCode',
    t->>'decorationTechnology',
    10,
    now()
  from json_array_elements(i_data  -> 'items') t
 returning fulfiller_id ,item_id ,order_id , status_id , item_updated_time;
 
-- returning fulfiller_id ,item_id ,order_id , status_id, item_updated_time;
 

end;
$function$
LANGUAGE plpgsql;

运行存储函数的示例数据

select * from post_items('{"orderId": "s",
 "fulfillerId":"kv0fdt6cx7",
"orderDetailsUrl":"het",
"items":[
    {
        "decorationTechnology":"laserEngraving","itemDescription":"Test Sku for Oracle testing",
"itemId":"aagasdsam1",
        "manufacturingUrl":"h-d9ccea00cn-prepress",
        "skuCode":"CIM-QYXB3789","productName":"Tsdacle testing","quantity":"225","taskId":"33a1sd769876c52"
    },
    {
         "decorationTechnology":"ssdas"
         "itemDescription":"Test Sku for satesting",
         "itemId":"aagam2",
         "manufacturingUrl":"httsadfa2d72-f225-4a03-addd-d9ccea00c874~1sadlpen-spress",
         "skuCode":"CXB3789",
         "productName":"Test Sku for Oracle testing",
         "quantity":"225",
         "taskId":"33asad6c52"
    }
]
}'::json)

当我尝试运行时，函数值被插入到数据库中，但没有收到任何回报。

预期输出 返回Stored函数返回查询中提到的参数

尝试了多种方法，但总是没有输出

Answer 1

你需要添加：

...
returning fulfiller_id ,item_id ,order_id , status_id , item_updated_time;
RETURN NEXT;
RETURN;

...

从这里开始：

https://www.postgresql.org/docs/12/plpgsql-control-structures.html#PLPGSQL-STATEMENTS-RETURNING

42.6.1.2。返回下一个并返回查询

RETURN NEXT 和 RETURN QUERY 实际上并不从函数返回——它们只是将零或多行附加到函数的结果集中。然后继续执行 PL/pgSQL 函数中的下一条语句。随着连续的 RETURN NEXT 或 RETURN QUERY 命令被执行，结果集被建立起来。最后的 RETURN 应该没有参数，导致控制退出函数（或者你可以让控制到达函数的末尾）。 .

RETURNS table 是RETURNS setof 的别名，因此您需要使用RETURN NEXT 返回一个集合。

更新

我的错。我想我记得RETURN NEXT 会自动提取出变量。要完成这项工作，您需要将RETURNING 中的值分配给RETURN NEXT 之前的out(table) 变量。例如：

\d names
                       Table "public.names"
 Column |          Type          | Collation | Nullable | Default 
--------+------------------------+-----------+----------+---------
 id     | integer                |           | not null | 
 name   | character varying(200) |           | not null | 
 animal | character varying(200) |           | not null | 
Indexes:
    "names_pkey" PRIMARY KEY, btree (id)

CREATE OR REPLACE FUNCTION public.return_test(id_in integer, name_in character varying, animal_in character varying)
 RETURNS TABLE(id_out integer, name_out character varying, animal_out character varying)
 LANGUAGE plpgsql
AS $function$

BEGIN

    INSERT INTO
        names (id, name, animal)
    VALUES
        (id_in, name_in, animal_in)
    RETURNING id, name, animal INTO id_out, name_out, animal_out;

RETURN NEXT;
RETURN;
END;

$function$


select * from  return_test(1, 'ranger', 'dog');

 id_out | name_out | animal_out 
--------+----------+------------
      1 | ranger   | dog
(1 row)