【问题标题】:iOS13/iPadOS13 modal view controller automatic swipe to dismiss break view that captures touchiOS13/iPadOS13 模态视图控制器自动滑动关闭捕捉触摸的中断视图
【发布时间】:2020-08-07 18:17:37
【问题描述】:

我找到了这个帖子,但它没有反映我的情况:Disable gesture to pull down form/page sheet modal presentation

我有这个问题:我的应用程序通过表单格式的模态演示打开一个小视图控制器。提供了一个包含静态 tableviewcontroller 的导航控制器,在唯一的单元格内我有一个通过“touchesBegan”和“touchesMoved”捕获签名的视图。

当我尝试绘制签名时,触摸被视图控制器捕获,它试图自行关闭。

显然我已经激活了属性“modalInPresentation”

我如何找到对此负责的gestureRecognizer?

self.view.gestureRecognizers He gives me these back, but nobody seems to intercept the gesture of dismiss:

<UIScrollViewDelayedTouchesBeganGestureRecognizer: 0x280ac8800; state = Possible; enabled = NO; delaysTouchesBegan = YES; view = <UITableView 0x10711a000>; target= <(action=delayed:, target=<UITableView 0x10711a000>)>>
<UIScrollViewPanGestureRecognizer: 0x105bfe170; state = Possible; enabled = NO; delaysTouchesEnded = NO; view = <UITableView 0x10711a000>; target= <(action=handlePan:, target=<UITableView 0x10711a000>)>>
<UIScrollViewKnobLongPressGestureRecognizer: 0x105b9b270; state = Possible; view = <UITableView 0x10711a000>; target= <(action=_handleKnobLongPressGesture:, target=<UITableView 0x10711a000>)>; numberOfTapsRequired = 0; minimumPressDuration = 0.1>
<UIScrollViewKnobLongPressGestureRecognizer: 0x105b9b440; state = Possible; view = <UITableView 0x10711a000>; target= <(action=_handleKnobLongPressGesture:, target=<UITableView 0x10711a000>)>; numberOfTapsRequired = 0>
<UIHoverGestureRecognizer: 0x112fb7f60; state = Possible; view = <UITableView 0x10711a000>; target= <(action=_handleKnobHoverGesture:, target=<UITableView 0x10711a000>)>>
<_UIDragAutoScrollGestureRecognizer: 0x28098ec10; state = Possible; cancelsTouchesInView = NO; delaysTouchesEnded = NO; view = <UITableView 0x10711a000>; target= <(action=_handleAutoScroll:, target=<UITableView 0x10711a000>)>>
<_UISwipeActionPanGestureRecognizer: 0x105be9d00; state = Possible; view = <UITableView 0x10711a000>; target= <(action=_swipeRecognizerDidRecognize:, target=<_UISwipeHandler 0x281896b00>)>>
<_UISwipeDismissalGestureRecognizer: 0x280ac8d00; state = Possible; enabled = NO; delaysTouchesBegan = YES; view = <UITableView 0x10711a000>; target= <(action=_dismissalRecognizerDidRecognize:, target=<_UISwipeHandler 0x281896b00>)>>

【问题讨论】:

  • 如果你使用的是 pushViewController 那么你需要展示这个 popviewController..

标签: ios uigesturerecognizer ios13 modalviewcontroller ipados13


【解决方案1】:
【解决方案2】:

应该是这个

<UIDropShadowView: 0x10521faf0; frame = (0 40; 375 627); gestureRecognizers = <NSArray: 0x2803a5f50>; layer = <CALayer: 0x280de8e00>>
(lldb) po [self.view _parentDescription]
<UIView: 0x10521dac0; frame = (0 0; 375 627); autoresize = W+H; gestureRecognizers = <NSArray: 0x2803a5bc0>; layer = <CALayer: 0x280de87c0>>
    <UIView: 0x105220880; frame = (0 0; 375 627); clipsToBounds = YES; autoresize = W+H; layer = <CALayer: 0x280de8d40>>
        <UIView: 0x105220380; frame = (0 0; 375 627); clipsToBounds = YES; autoresize = W+H; layer = <CALayer: 0x280de8d60>>
            <UIDropShadowView: 0x10521faf0; frame = (0 40; 375 627); gestureRecognizers = <NSArray: 0x2803a5f50>; layer = <CALayer: 0x280de8e00>>
                <UITransitionView: 0x10521f540; frame = (0 0; 375 667); autoresize = W+H; layer = <CALayer: 0x280de8d20>>
                    <UIWindow: 0x105106ac0; frame = (0 0; 375 667); autoresize = W+H; gestureRecognizers = <NSArray: 0x2803ad230>; layer = <UIWindowLayer: 0x280ded800>>

【讨论】:

    【解决方案3】:

    如果您使用的是 pushViewController,那么您需要展示这个 popviewController。 像这样。

    let vc = storyboard?.instantiateViewController(withIdentifier: "popSignatureViewController") as? popSignatureViewController
            vc?.modalPresentationStyle = .overCurrentContext
            self.present(vc!, animated: true, completion: nil)
    

    【讨论】:

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