passport.js 使用 mysql 连接反序列化用户答案

【问题标题】：passport.js deserialize user with mysql connectionpassport.js 使用 mysql 连接反序列化用户
【发布时间】：2022-01-21 21:17:13
【问题描述】：

当我将它连接到数据库时，如何反序列化 passport.js 中的用户？当我使用数组时它可以工作，但是一旦它连接到数据库它就停止工作。我该如何解决？

Error: Failed to deserialize user out of session
    at pass (/Users/frederik/IdeaProjects/vr/node_modules/passport/lib/authenticator.js:341:19)
    at deserialized (/Users/frederik/IdeaProjects/vr/node_modules/passport/lib/authenticator.js:346:7)
    at /Users/frederik/IdeaProjects/vr/src/login/passport-config.ts:42:54
    at pass (/Users/frederik/IdeaProjects/vr/node_modules/passport/lib/authenticator.js:354:9)
    at Authenticator.deserializeUser (/Users/frederik/IdeaProjects/vr/node_modules/passport/lib/authenticator.js:359:5)
    at SessionStrategy.authenticate (/Users/frederik/IdeaProjects/vr/node_modules/passport/lib/strategies/session.js:61:10)
    at attempt (/Users/frederik/IdeaProjects/vr/node_modules/passport/lib/middleware/authenticate.js:369:16)
    at authenticate (/Users/frederik/IdeaProjects/vr/node_modules/passport/lib/middleware/authenticate.js:370:7)
    at Layer.handle [as handle_request] (/Users/frederik/IdeaProjects/vr/node_modules/express/lib/router/layer.js:95:5)
    at trim_prefix (/Users/frederik/IdeaProjects/vr/node_modules/express/lib/router/index.js:323:13)

const authenticateUserDB = (email: string, password: string, done: any) => {
        sql._getInstance()._getConnection().query('SELECT * FROM `users` WHERE ?',{email:email}, function (error:MysqlError|null, results:any) {
            if (error) return done(error, false, "No database connection");
            if(results.length == 0) return done(null, false, "No User with that email");
            //TODO:encrypt
            if(password == results[0].password){
                return done(null, {
                    id: results[0]['uuid'],
                    name: results[0]['name'],
                    email: results[0]['email'],
                    password: results[0]['password']
                });
            }else{
                return done(null, false, "Password is incorect");
            }
        });
    }

    const getUserByUUID = (uuid:string)=>{
        sql._getInstance()._getConnection().query('SELECT * FROM `users` WHERE ?',{uuid:uuid}, function (error:MysqlError|null, results:any) {
            if (error) throw Error();
            if(results.length == 0) throw Error();
            return {
                id: results[0]['uuid'],
                name: results[0]['name'],
                email: results[0]['email'],
            }

        });
    }

    passport.use(new Strategy({usernameField: 'email'}, authenticateUserDB));
    passport.serializeUser((user: any, done: any) => done(null, user.id));
    passport.deserializeUser((id: any, done: any) => done(null, getUserByUUID(id)));

【问题讨论】：

标签： javascript node.js typescript passport.js

【解决方案1】：

问题是反序列化没有等待 getUserByUUid

const getUserByUUID = (uuid: string) => {
        return new Promise((resolve, reject) => {
            sql._getInstance()._getConnection().query('SELECT * FROM `users` WHERE ?', {uuid: uuid}, function (error: MysqlError | null, results: any) {
                if (error) reject("");
                if (results.length == 0) reject("");
                resolve({
                    id: results[0]['uuid'],
                    name: results[0]['name'],
                    email: results[0]['email'],
                    password: results[0]['password']
                });

            });
        })

    }
passport.deserializeUser(async (id: any, done: any) => done(null, await getUserByUUID(id)));

【讨论】：