【发布时间】:2017-07-29 01:07:46
【问题描述】:
我在模型文件中定义了一个常量变量,并尝试在将数据插入表时访问此常量变量,然后它显示未定义。我正在使用 sequlaize ORM 和 nodejs。我想为状态定义三个值,例如 Active = 1、Inactive = 2、Deleted = 3,或者是否有任何其他解决方案来定义它。我正在使用续集 ORM 4+ 版本。
Model code is here
var Sequalize = require('sequelize');
var sequalize = require('../../config/db_config');
const ACTIVE = '1';
const INACTIVE = '2';
const DELETED = '3';
const User = sequalize.define('user',{
user_id_pk : {
type : Sequelize.INTEGER,
allowNull : false,
primaryKey : true,
autoIncrement : true
},
user_type : Sequelize.INTEGER,
first_name : Sequelize.STRING,
middle_name : Sequelize.STRING,
last_name : Sequelize.STRING,
password : Sequelize.STRING,
email : Sequelize.STRING,
mobile_no : Sequelize.STRING,
is_email_verified : {
type:Sequalize.INTEGER,
defaultValue : 0
},
gender : Sequelize.STRING,
profile_image: Sequelize.STRING,
dob : Sequelize.DATE,
is_active : Sequelize.STRING,
created_date : Sequelize.DATE,
created_by : Sequelize.INTEGER,
updated_date : Sequelize.DATE,
updated_by : Sequelize.INTEGER,
},{
timestamps: false,
paranoid: true,
underscored: true,
freezeTableName: true,
tableName: 'user',
createdAt:'created_date',
updatedAt:'updated_date'
});
User.sync({force:false}).then(() => {
console.log('Table is created!');
}).catch(err => {
console.log('An error occur when table is created!');
});
module.exports = User;
Controller code is here
userController.saveUser = function(req,res){
console.log(user.ACTIVE);return false;
user.findOrCreate({
where:{
first_name: req.body.first_name,
email: req.body.email,
boltt_code: req.body.boltt_code
},
defaults:{
first_name: req.body.fihhrst_name,
middle_name : 'Rajeev',
last_name : 'Varshney',
email: req.body.email,
boltt_code: req.body.boltt_code,
is_active : '1',
}
})
.spread( function(user, created) {
var msg = '';
if(created){
msg = 'User inserted successfully!';
}else{
msg = 'User already exist!';
}
res.status(200).send({error : false,message : msg2, data : user });
})
.catch((err) => {
console.log('Oops something wrong! ' + err);
});
};
【问题讨论】:
-
这个问题和MySQL有什么关系?
-
我确定您使用它,但我在问题中看不到任何与 MySQL 相关的内容。您应该删除 MySQL 标签并添加 sequelize.js 标签。如果您仔细观察,库的名称是
Sequelize,而不是您拼错的“Sequalize”。然后你想知道为什么代码不起作用...... -
我的意思是,在代码中。它充满了
Sequalize.INTEGER。即使Google knows也应该是Sequelize.INTEGER
标签: node.js sequelize.js