【问题标题】:Send file via IdTCPServer upon request of client根据客户端的请求通过 IdTCPServer 发送文件
【发布时间】:2017-05-18 05:08:04
【问题描述】:

如果执行客户端请求,我正在尝试通过 TCP 服务器发送文本文件。互联网上的示例要么已过时,要么无用。我知道我应该使用流,但我不明白该怎么做。

我改编了我在互联网上找到的代码,但我对流感到困惑。有人可以指导我正确的方向吗?

服务器:

TForm2.bStartClick(Sender: TObject);
begin
  if not IdTCPServer1.Active then
  begin
    IdTCPServer1.Active := True;
    Log('Server started on port ' + IntToStr(IdTCPServer1.DefaultPort));
    bStart.Enabled := False;
    bStop.Enabled := True;
  end;
end;

procedure TForm2.bStopClick(Sender: TObject);
begin
  if IdTCPServer1.Active then
  begin
    IdTCPServer1.Active := False;
    Log('Server stopped');
    bStop.Enabled := False;
    bStart.Enabled := True;
  end;
end;

procedure TForm2.FormCreate(Sender: TObject);
begin
  bStart.Enabled := True;
  bStop.Enabled := False;
end;

procedure TForm2.IdTCPServer1Execute(AContext: TIdContext);
var
  s: string;   FS:TFileStream;
begin

  if s ='1' then
  begin
    FS := TFileStream.Create(MyPath, fmOpenShare);
    try
      AContext.Connection.WriteStream(FS);
    finally
      FS.Free;
    end;
  end;

end;

procedure TForm2.Log(const s: string);
begin
  mLog.Lines.Add(s);
end

客户:

procedure TForm1.bConnectClick(Sender: TObject);
begin
  IdTCPClient1.Host := eServer.Text;
  IdTCPClient1.Port := StrToInt(ePort.Text);
  IdTCPClient1.Connect;

  if IdTCPClient1.Connected then
  begin
    Log('Connected to ' + IdTCPClient1.Host + ':' +
      IntToStr(IdTCPClient1.Port));
    bConnect.Enabled := False;
    bDisconnect.Enabled := True;
    bSend.Enabled := True;
  end;
end;

procedure TForm1.bDisconnectClick(Sender: TObject);
begin
  IdTCPClient1.Disconnect;
  bDisconnect.Enabled := False;
  bConnect.Enabled := True;
  bSend.Enabled := False;
end;

procedure TForm1.bSendClick(Sender: TObject);
var
  FS: TFileStream;
begin
//  IdTCPClient1.IOHandler.WriteLn(eTextToSend.Text);

  FS := TFileStream.Create('C:\Users\xxx\Desktop\test.txt', fmCreate);
  try
    IdTCPClient1.ReadStream(FS);
  finally
    Fs.Free;
  end;


end;

procedure TForm1.FormCreate(Sender: TObject);
begin
  bDisconnect.Enabled := False;
  bSend.Enabled := False;
end;

procedure TForm1.Log(const s: string);
begin
  mLog.Lines.Add(s);
end;

【问题讨论】:

    标签: delphi-7 tcpclient indy tcpserver


    【解决方案1】:

    您的客户端没有向服务器发送任何命令,并且服务器在发送文件之前也没有等待任何命令。

    但是,除此之外,您的代码无论如何都不会编译,因为TIdTCPConnection 没有WriteStream()ReadStream() 方法。正确的方法是TIdIOHandler.Write(TStream)TIdIOHandler.ReadStream()

    但即便如此,您对写入流和读取流的调用也不匹配,因为默认情况下Write(TStream) 不会将流大小发送给对等方,但默认情况下ReadStream() 确实希望接收流大小。

    尝试类似的方法:

    服务器:

    procedure TForm2.IdTCPServer1Execute(AContext: TIdContext);
    var
      s: string;
      FS: TFileStream;
    begin
      s := AContext.Connection.IOHandler.ReadLn;
      if s = 'SENDFILE' then
      begin
        try
          FS := TFileStream.Create(MyPath, fmOpenRead or fmShareDenyWrite);
        except
          AContext.Connection.IOHandler.WriteLn('500 Cannot open file');
          Exit;
        end;
        try
          AContext.Connection.IOHandler.WriteLn('200 Sending file');
          AContext.Connection.IOHandler.LargeStream := True;
          AContext.Connection.IOHandler.Write(FS, 0, True);
        finally
          FS.Free;
        end;
      end
      else    
        AContext.Connection.IOHandler.WriteLn('500 Unknown command');
    end;
    

    客户:

    procedure TForm1.bSendClick(Sender: TObject);
    var
      FS: TFileStream;
    begin
      FS := TFileStream.Create('C:\Users\xxx\Desktop\test.txt', fmCreate);
      try
        try
          IdTCPClient1.IOHandler.SendCmd('SENDFILE', 200);
          IdTCPClient1.IOHandler.LargeStream := True;
          IdTCPClient1.IOHandler.ReadStream(FS, -1, False);
        finally
          FS.Free;
        end;
      except
        DeleteFile('C:\Users\xxx\Desktop\test.txt');
        raise;
      end;
    end;
    

    在这种情况下,您可以考虑改用TIdCmdTCPServer,然后您可以使用其CommandHandlers 集合在设计时直观地定义您的命令,并分配OnCommand 事件处理程序以在运行时处理它们,例如:

    // OnCommand handler for 'SENDFILE' command
    procedure TForm2.IdCmdTCPServer1SENDFILECommand(ASender: TIdCommand);
    var
      FS: TFileStream;
    begin
      try
        FS := TFileStream.Create(MyPath, fmOpenRead or fmShareDenyWrite);
      except
        ASender.SetReply(500, 'Cannot open file');
        Exit;
      end;
      try
        ASender.SetReply(200, 'Sending file');
        ASender.SendReply;
        AContext.Connection.IOHandler.LargeStream := True;
        AContext.Connection.IOHandler.Write(FS, 0, True);
      finally
        FS.Free;
      end;
    end;
    

    【讨论】:

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