【问题标题】:How to wrap object in a Promise?如何将对象包装在 Promise 中?
【发布时间】:2015-06-29 12:39:28
【问题描述】:

我有一个代码在内存存储中搜索一些数据,如果没有找到,则在服务器上搜索该数据并将其缓存在内存中。 如何将对象作为 Promise 返回,以便调用者可以在其上调用“完成”?

代码如下:

if (foundInLocalStorage)
    {
    // This part I cannot make to work, caller does not have its 'done' fired
        var defered = $.Deferred();
        defered.resolve();
        defered.promise(dataFound);
    }
    else
    {
        return $.ajax
            (
            {
                url: someUrl,
                dataType: 'json',
                data: { id: 101 }
            }
            )

            .done
            (
//That part is fine
              ......

            );
    }

【问题讨论】:

    标签: javascript jquery promise


    【解决方案1】:

    你需要返回一个承诺

    if (foundInLocalStorage) {
        var defered = $.Deferred();
        defered.resolve(dataFound);//resolve the promise with the data found
        //or setTimeout(defered.resolve.bind(promise, 5)); if you want to maintain the async nature
        return defered.promise();//return a promise
    
    } else {
        return $.ajax({
            url: someUrl,
            dataType: 'json',
            data: {
                id: 101
            }
        }).done(
        //That part is fine
        ......
    
        );
    }
    

    【讨论】:

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