Oracle 18c 之后的解决方案
我认为这在 18c 之前不起作用(如果我错了,请纠正我),但现在我们可以查询 ALL_PLSQL_TYPE_ATTRS 视图:
SELECT type_name, attr_name, attr_type_name, length
FROM all_plsql_type_attrs
WHERE package_name = 'TEST_PACKAGE'
ORDER BY owner, package_name, type_name, attr_no;
要得到这样的东西:
TYPE_NAME ATTR_NAME ATTR_TYPE_NAME LENGTH
------------------------------------------------------
PERSON_RECORD_TYPE FIRST_NAME VARCHAR2 1000
PERSON_RECORD_TYPE LAST_NAME VARCHAR2 1000
Oracle 18c 之前的解决方案
jOOQ's code generator 在内部使用以下查询可靠地找到所有包级别 PL/SQL RECORD 类型:
SELECT
"x"."TYPE_OWNER",
"x"."TYPE_NAME",
"x"."TYPE_SUBNAME","a".subprogram_id,
"a"."ARGUMENT_NAME" "ATTR_NAME",
"a"."SEQUENCE" "ATTR_NO",
"a"."TYPE_OWNER" "ATTR_TYPE_OWNER",
nvl2("a"."TYPE_SUBNAME", "a"."TYPE_NAME", NULL) "package_name",
COALESCE("a"."TYPE_SUBNAME", "a"."TYPE_NAME", "a"."DATA_TYPE") "ATTR_TYPE_NAME",
"a"."DATA_LENGTH" "LENGTH",
"a"."DATA_PRECISION" "PRECISION",
"a"."DATA_SCALE" "SCALE"
FROM "SYS"."ALL_ARGUMENTS" "a"
JOIN (
SELECT
"a"."TYPE_OWNER",
"a"."TYPE_NAME",
"a"."TYPE_SUBNAME",
MIN("a"."OWNER") KEEP (DENSE_RANK FIRST
ORDER BY "a"."OWNER" ASC, "a"."PACKAGE_NAME" ASC,
"a"."SUBPROGRAM_ID" ASC, "a"."SEQUENCE" ASC) "OWNER",
MIN("a"."PACKAGE_NAME") KEEP (DENSE_RANK FIRST
ORDER BY "a"."OWNER" ASC, "a"."PACKAGE_NAME" ASC,
"a"."SUBPROGRAM_ID" ASC, "a"."SEQUENCE" ASC) "PACKAGE_NAME",
MIN("a"."SUBPROGRAM_ID") KEEP (DENSE_RANK FIRST
ORDER BY "a"."OWNER" ASC, "a"."PACKAGE_NAME" ASC,
"a"."SUBPROGRAM_ID" ASC, "a"."SEQUENCE" ASC) "SUBPROGRAM_ID",
MIN("a"."SEQUENCE") KEEP (DENSE_RANK FIRST
ORDER BY "a"."OWNER" ASC, "a"."PACKAGE_NAME" ASC,
"a"."SUBPROGRAM_ID" ASC, "a"."SEQUENCE" ASC) "SEQUENCE",
MIN("next_sibling") KEEP (DENSE_RANK FIRST
ORDER BY "a"."OWNER" ASC, "a"."PACKAGE_NAME" ASC,
"a"."SUBPROGRAM_ID" ASC, "a"."SEQUENCE" ASC) "next_sibling",
MIN("a"."DATA_LEVEL") KEEP (DENSE_RANK FIRST
ORDER BY "a"."OWNER" ASC, "a"."PACKAGE_NAME" ASC,
"a"."SUBPROGRAM_ID" ASC, "a"."SEQUENCE" ASC) "DATA_LEVEL"
FROM (
SELECT
lead("a"."SEQUENCE", 1, 99999999) OVER (
PARTITION BY "a"."OWNER", "a"."PACKAGE_NAME",
"a"."SUBPROGRAM_ID", "a"."DATA_LEVEL"
ORDER BY "a"."SEQUENCE" ASC
) "next_sibling",
"a"."TYPE_OWNER",
"a"."TYPE_NAME",
"a"."TYPE_SUBNAME",
"a"."OWNER",
"a"."PACKAGE_NAME",
"a"."SUBPROGRAM_ID",
"a"."SEQUENCE",
"a"."DATA_LEVEL",
"a"."DATA_TYPE"
FROM "SYS"."ALL_ARGUMENTS" "a"
WHERE "a"."OWNER" IN ('TEST') -- Possibly replace schema here
) "a"
WHERE ("a"."TYPE_OWNER" IN ('TEST') -- Possibly replace schema here
AND "a"."OWNER" IN ('TEST') -- Possibly replace schema here
AND "a"."DATA_TYPE" = 'PL/SQL RECORD')
GROUP BY
"a"."TYPE_OWNER",
"a"."TYPE_NAME",
"a"."TYPE_SUBNAME"
) "x"
ON (("a"."OWNER", "a"."PACKAGE_NAME", "a"."SUBPROGRAM_ID")
= (("x"."OWNER", "x"."PACKAGE_NAME", "x"."SUBPROGRAM_ID"))
AND "a"."SEQUENCE" BETWEEN "x"."SEQUENCE" AND "next_sibling"
AND "a"."DATA_LEVEL" = ("x"."DATA_LEVEL" + 1))
ORDER BY
"x"."TYPE_OWNER" ASC,
"x"."TYPE_NAME" ASC,
"x"."TYPE_SUBNAME" ASC,
"a"."SEQUENCE" ASC
在您的情况下,结果将类似于:
TYPE_NAME TYPE_SUBNAME ATTR_NAME ATTR_TYPE_NAME LENGTH
----------------------------------------------------------------------
TEST_PACKAGE PERSON_RECORD_TYPE FIRST_NAME VARCHAR2 1000
TEST_PACKAGE PERSON_RECORD_TYPE LAST_NAME VARCHAR2 1000
当前限制:
- 该查询将仅查找至少在某处被另一种类型和/或过程引用的那些类型。这是从查询中的
ALL_ARGUMENTS 字典视图继承而来的限制。
-
%ROWTYPE 类型未正确返回,因为行类型未从 TYPE_NAME / TYPE_SUBNAME 列中引用。
更多信息在这里:
https://blog.jooq.org/2016/11/08/use-jooq-to-read-write-oracle-plsql-record-types