【发布时间】:2020-10-28 02:33:09
【问题描述】:
我有一个返回数据的函数。该数据来自一个带有属性名称的接口。输出具有属性名称。如果可能的话,我想避免这种情况。
我该怎么做?
界面:
export interface DataNode {
id?: number,
type?: string,
parentId?: number,
data?: any,
children?: DataNode[],
buildings?: DataNode[],
areas?: DataNode[],
rooms?: DataNode[],
flags?: DataNode[],
details?: DataNode[]
};
创建输出的代码:
export const fromCity = async (
city: entities.City,
depth: "none" | "immediate" | "full"
): Promise<DataNode> => {
return {
id: city.id,
type: "City",
data: {
name: city.name,
title: city.title,
// created: city.created,
// updatedAt: city.updatedAt
},
buildings: depth !== "none" ?
await mapChildren((building: entities.Building): Promise<DataNode> => {
building.city = building.city || Promise.resolve(city);
return fromBuilding(
building,
depth === "immediate" ? "none" : depth
);
})(await (city.buildings || Promise.resolve([]))) : []
};
};
我从 API 得到的实际输出:
"id": 1,
"type": "Building",
"parentId": 1,
"data": {
"name": "data-center",
"title": "Data Center",
"subtitle": "Secure Data Center and Cloud NOC",
"x": "11.30",
"y": "41.50"
我想从 API 中得到什么:
"id": 1,
"type": "Building",
"parentId": 1,
{
"name": "data-center",
"title": "Data Center",
"subtitle": "Secure Data Center and Cloud NOC",
"x": "11.30",
"y": "41.50"
注意"data": 的消失。这就是我想要隐藏的。
有没有简单的方法来告诉“不要返回这个属性名,只返回它的值”?
【问题讨论】:
标签: javascript node.js typescript api