【发布时间】:2015-11-06 07:38:25
【问题描述】:
我发现了这个非常好的复选框按钮样式(下面的链接),并且一直在尝试使用 jQuery 打开和关闭它。我之前没有使用过很多伪类,通常我只是添加一个“活动”类。
https://proto.io/freebies/onoff/
我需要在页面加载时根据服务器响应打开或关闭按钮,但我似乎无法在不破坏 CSS 的情况下操作 CSS。我该如何激活/停用此按钮?
.onoffswitch {
position: relative;
width: 90px;
-webkit-user-select: none;
-moz-user-select: none;
-ms-user-select: none;
}
.onoffswitch-checkbox {
display: none;
}
.onoffswitch-label {
display: block;
overflow: hidden;
cursor: pointer;
border: 2px solid #999999;
border-radius: 20px;
}
.onoffswitch-inner {
display: block;
width: 200%;
margin-left: -100%;
transition: margin 0.3s ease-in 0s;
}
.onoffswitch-inner:before,
.onoffswitch-inner:after {
display: block;
float: left;
width: 50%;
height: 30px;
padding: 0;
line-height: 30px;
font-size: 14px;
color: white;
font-family: Trebuchet, Arial, sans-serif;
font-weight: bold;
box-sizing: border-box;
}
.onoffswitch-inner:before {
content: "ON";
padding-left: 10px;
background-color: #34A7C1;
color: #FFFFFF;
}
.onoffswitch-inner:after {
content: "OFF";
padding-right: 10px;
background-color: #EEEEEE;
color: #999999;
text-align: right;
}
.onoffswitch-switch {
display: block;
width: 18px;
margin: 6px;
background: #FFFFFF;
position: absolute;
top: 0;
bottom: 0;
right: 56px;
border: 2px solid #999999;
border-radius: 20px;
transition: all 0.3s ease-in 0s;
}
.onoffswitch-checkbox:checked + .onoffswitch-label .onoffswitch-inner {
margin-left: 0;
}
.onoffswitch-checkbox:checked + .onoffswitch-label .onoffswitch-switch {
right: 0px;
}
<div class="onoffswitch">
<input type="checkbox" name="onoffswitch" class="onoffswitch-checkbox" id="myonoffswitch" checked>
<label class="onoffswitch-label" for="myonoffswitch">
<span class="onoffswitch-inner"></span>
<span class="onoffswitch-switch"></span>
</label>
</div>
【问题讨论】:
-
您不添加和删除伪类。它们只是基于元素的状态。
-
您想以编程方式切换元素吗?切换的视觉状态由输入的
checked状态决定,因此更改checked状态将改变切换的外观。 -
正如@showdev所说,css按钮的状态基于复选框的状态。只需将复选框设置为 checked=true,css 按钮就会反映这一点。
标签: jquery html css pseudo-class