滚动列表视图答案

【问题标题】：scrolling through list view滚动列表视图
【发布时间】：2011-09-21 15:15:08
【问题描述】：

在我的应用程序中，我使用基本适配器在列表视图中显示大陆。我想在列表中显示 2 个文本视图和 1 个图像视图。图像视图在标志条件下显示。第一次显示所有内容正确。但是如果我滚动列表中的意外行为，我们在那里。图像视图显示在标志为假的行上。下面是我的代码... 请帮帮我！！！！

public class MyAdapter extends BaseAdapter
    { 
        private Context context;
        Views viewsList;
        private ArrayList<Views> selectedItems = new ArrayList<Views>();

        public MyAdapter(Context c, int textViewResourceId,
                ArrayList<Views> list) {
            super();
            this.context=c;

            this.selectedItems=list;
        }


        public int getCount() {

            return selectedItems.size();
        }

        public Object getItem(int position) {

            return selectedItems.get(position);
        }

        public long getItemId(int position) {

            return position;
        }

        public View getView(int position, View convertView, ViewGroup parent) {
            viewsList=selectedItems.get(position);
            myAdapter.notifyDataSetChanged();
            View v=convertView; 
            ImageView tipImageView;
            LayoutInflater inflater = (LayoutInflater) context.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
            TextView bTitle,textVies,likeView;
            if (v == null) {

                v = inflater.inflate(R.layout.tips_viwes_and_like_gui, null);

                bTitle = (TextView) v.findViewById(R.id.textname);
                bTitle.setText(viewsList.getName());

                if(viewsList.getContaisImage().contains("1"))
                {
                    tipImageView=(ImageView)v.findViewById(R.id.setImageId);
                    tipImageView.setImageResource(R.drawable.tip_image);
                }
                else if(viewsList.getContaisImage().contains("0"))
                {
                    tipImageView=null;
                }

                 textVies = (TextView) v.findViewById(R.id.textviews);
                textVies.setText("Views :"+viewsList.getViewsId());

                likeView=(TextView) v.findViewById(R.id.textLike);
                likeView.setText("Like :"+viewsList.getLike());
            }
            return v;
        }
    }

【问题讨论】：

一切都在if(v==null)。保留第一行 v = inflater.inflate(R.layout.tips_viwes_and_like_gui, null); 并删除所有内容，将其从 if 语句 中取出
@Sherif..感谢您的回复....但没有运气....

标签： android

【解决方案1】：

这是一个很常见的问题，你必须写下这一行的 else 部分试试这个方法

public View getView(int position, View convertView, ViewGroup parent) {
            viewsList=selectedItems.get(position);
            myAdapter.notifyDataSetChanged();
            View v=converView; 
            ImageView tipImageView;
            LayoutInflater inflater = (LayoutInflater) context.getSystemService(Context.LAYOUT_INFLATER_SERVICE);
            TextView bTitle,textVies,likeView;

            if (v == null) {
                v = inflater.inflate(R.layout.tips_viwes_and_like_gui, null);    

                bTitle = (TextView) v.findViewById(R.id.textname);
                textVies = (TextView) v.findViewById(R.id.textviews);
                likeView=(TextView) v.findViewById(R.id.textLike);
                tipImageView=(ImageView)v.findViewById(R.id.setImageId);
            }

            bTitle.setText(viewsList.getName());
            likeView.setText("Like :"+viewsList.getLike());
            textVies.setText("Views :"+viewsList.getViewsId());
            tipImageView.setImageResource(R.drawable.tip_image);

            if(viewsList.getContaisImage().contains("0")){
               tipImageView.setVisibile(ImageView.GONE);
            }else{
               tipImageView.setVisibile(ImageView.VISIBLE);
            }

            return v;
        }

【讨论】：