【发布时间】：2014-09-17 10:09:57
【问题描述】：
我正在尝试按照教程获取 json 到 ListView，
这个应用程序只在json 中显示Array。
当我使用来自this site 的 url 源时，该应用程序可以完全运行
但是当我使用数据库中的本地数据json 时，总是会出错。
错误是
Error parsing data org.json.JSONException: Value <!-- of type java.lang.String
cannot be converted to JSONObject
并在第 99 行和第 68 行显示错误
这是我的代码
tes.html
<html>
<head></head>
<body>
{ "android": [ { "ver": "1.5", "name": "Cupcake", "api": "API level 3" },
{ "ver": "1.6", "name": "Donut", "api": "API level 4" },
{ "ver": "2.0-2.1", "name": "Eclair", "api": "API level 5-7" },
{ "ver": "2.2", "name": "Froyo", "api": "API level 8" },
{ "ver": "2.3", "name": "Gingerbread", "api": "API level 9-10" },
{ "ver": "3.0-3.2", "name": "Honeycomb", "api": "API level 11-13" },
{ "ver": "4.0", "name": "Ice Cream Sandwich", "api": "API level 14-15" },
{ "ver": "4.1-4.3", "name": "JellyBean", "api": "API level 16-18" },
{ "ver": "4.4", "name": "KitKat", "api": "API level 19" } ] }
<body>
</html>
这是我的 JSONParse 类
private class JSONParse extends AsyncTask<String, String, JSONObject> { // THIS LINE 68 ERROR
private ProgressDialog pDialog;
@Override
protected void onPreExecute() {
super.onPreExecute();
ver = (TextView) getActivity().findViewById(R.id.vers);
name = (TextView) getActivity().findViewById(R.id.name);
api = (TextView) getActivity().findViewById(R.id.api);
//head = (TextView) getActivity().findViewById(R.id.head);
//note = (TextView) getActivity().findViewById(R.id.note);
pDialog = new ProgressDialog(getActivity());
pDialog.setMessage("Getting Data ...");
pDialog.setIndeterminate(false);
pDialog.setCancelable(true);
pDialog.show();
}
@Override
protected JSONObject doInBackground(String... args) {
JSONParser jParser = new JSONParser();
// Getting JSON from URL
JSONObject json = jParser.makeHttpRequestWithoutParams(url);
return json;
}
@Override
protected void onPostExecute(JSONObject json) {
pDialog.dismiss();
try {
// Getting JSON Array from URL
android = json.getJSONArray(TAG_OS); //THIS LINE 99 ERROR
for(int i = 0; i < android.length(); i++) {
JSONObject c = android.getJSONObject(i);
// Storing JSON item in a Variable
String ver = c.getString(TAG_VER);
String name = c.getString(TAG_NAME);
String api = c.getString(TAG_API);
// Adding value HashMap key => value
HashMap<String, String> map = new HashMap<String, String>();
map.put(TAG_VER, ver);
map.put(TAG_NAME, name);
map.put(TAG_API, api);
oslist.add(map);
list=(ListView) getActivity().findViewById(R.id.list);
ListAdapter adapter = new SimpleAdapter(getActivity(),
oslist,
R.layout.list_v,
new String[] { TAG_VER,TAG_NAME, TAG_API },
new int[] { R.id.vers,R.id.name, R.id.api}
);
list.setAdapter(adapter);
list.setOnItemClickListener(new AdapterView.OnItemClickListener() {
@Override
public void onItemClick(AdapterView<?> parent, View view,
int position, long id) {
Toast.makeText(getActivity(), "You Clicked at " + oslist.get(+position).get("name"), Toast.LENGTH_SHORT).show();
}
});
}
} catch (JSONException e) {
e.printStackTrace();
}
}
}
这是我的 JSONObject
public JSONObject makeHttpRequestWithoutParams(String url) {
// Making HTTP request
try {
// defaultHttpClient
DefaultHttpClient httpClient = new DefaultHttpClient();
HttpPost httpPost = new HttpPost(url);
HttpResponse httpResponse = httpClient.execute(httpPost);
HttpEntity httpEntity = httpResponse.getEntity();
is = httpEntity.getContent();
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
try {
BufferedReader reader = new BufferedReader(new InputStreamReader(
is, "iso-8859-1"), 8);
StringBuilder sb = new StringBuilder();
String line = null;
while ((line = reader.readLine()) != null) {
sb.append(line + "\n");
}
is.close();
json = sb.toString();
} catch (Exception e) {
Log.e("Buffer Error", "Error converting result " + e.toString());
}
// try parse the string to a JSON object
try {
jObj = new JSONObject(json);
} catch (JSONException e) {
Log.e("JSON Parser", "Error parsing data " + e.toString());
}
// return JSON String
return jObj;
}
希望有人能帮助我，谢谢
【问题讨论】：
-
您确定要在该文件中包含 html 标签吗？我希望文件是
test.json，里面只有一个有效的 json 对象 -
错误清楚地表明您的 JSON 无效。在您的代码中使用之前，在浏览器插件中检查一次 JSON 的格式
-
如果您也发布完整的 Logcat 将会很有帮助....