【发布时间】:2021-02-09 06:47:08
【问题描述】:
我希望你从上面的网站打印最高票房列表(所有电影的排名、标题、周末、总票房和周电影的顺序)
示例输出:
排名:1
标题:哥斯拉
周末:9320 万美元
总额:9320 万美元
周数:1
排名:2
标题:邻居
【问题讨论】:
-
你能告诉我们你到目前为止尝试了什么吗?
我希望你从上面的网站打印最高票房列表(所有电影的排名、标题、周末、总票房和周电影的顺序)
示例输出:
排名:1
标题:哥斯拉
周末:9320 万美元
总额:9320 万美元
周数:1
排名:2
标题:邻居
【问题讨论】:
这只是BeautifulSoup提取这些实体的简单方法
from bs4 import BeautifulSoup
import urllib2
url = "http://www.imdb.com/chart/?ref_=nv_ch_cht_2"
data = urllib2.urlopen(url).read()
page = BeautifulSoup(data, 'html.parser')
rows = page.findAll("tr", {'class': ['odd', 'even']})
for tr in rows:
for data in tr.findAll("td", {'class': ['titleColumn', 'weeksColumn','ratingColumn']}):
print data.get_text()
P.S.-按你的意愿安排。
【讨论】:
titleColumn 给出了电影的排名,ratingColumn 给出了电影的总分。
Scrapy 或 pyQt 或 webscrapping 库来刮东西。
lxml,我没有做太多,但这可能会对你有所帮助 - ianbicking.org/blog/2008/12/…
没有必要刮任何东西。请参阅我在这里给出的答案。
【讨论】:
下面的 Python 脚本将为您提供,
1) 来自 IMDb 的顶级票房电影列表
2) 以及 演员列表他们每个人。
from lxml.html import parse
def imdb_bo(no_of_movies=5):
bo_url = 'http://www.imdb.com/chart/'
bo_page = parse(bo_url).getroot()
bo_table = bo_page.cssselect('table.chart')
bo_total = len(bo_table[0][2])
if no_of_movies <= bo_total:
count = no_of_movies
else:
count = bo_total
movies = {}
for i in range(0, count):
mo = {}
mo['url'] = 'http://www.imdb.com'+bo_page.cssselect('td.titleColumn')[i][0].get('href')
mo['title'] = bo_page.cssselect('td.titleColumn')[i][0].text_content().strip()
mo['year'] = bo_page.cssselect('td.titleColumn')[i][1].text_content().strip(" ()")
mo['weekend'] = bo_page.cssselect('td.ratingColumn')[i*2].text_content().strip()
mo['gross'] = bo_page.cssselect('td.ratingColumn')[(i*2)+1][0].text_content().strip()
mo['weeks'] = bo_page.cssselect('td.weeksColumn')[i].text_content().strip()
m_page = parse(mo['url']).getroot()
m_casttable = m_page.cssselect('table.cast_list')
flag = 0
mo['cast'] = []
for cast in m_casttable[0]:
if flag == 0:
flag = 1
else:
m_starname = cast[1][0][0].text_content().strip()
mo['cast'].append(m_starname)
movies[i] = mo
return movies
if __name__ == '__main__':
no_of_movies = raw_input("Enter no. of Box office movies to display:")
bo_movies = imdb_bo(int(no_of_movies))
for k,v in bo_movies.iteritems():
print '#'+str(k+1)+' '+v['title']+' ('+v['year']+')'
print 'URL: '+v['url']
print 'Weekend: '+v['weekend']
print 'Gross: '+v['gross']
print 'Weeks: '+v['weeks']
print 'Cast: '+', '.join(v['cast'])
print '\n'
输出(在终端中运行):
parag@parag-innovate:~/python$ python imdb_bo_scraper.py
Enter no. of Box office movies to display:3
#1 Cinderella (2015)
URL: http://www.imdb.com/title/tt1661199?ref_=cht_bo_1
Weekend: $67.88M
Gross: $67.88M
Weeks: 1
Cast: Cate Blanchett, Lily James, Richard Madden, Helena Bonham Carter, Nonso Anozie, Stellan Skarsgård, Sophie McShera, Holliday Grainger, Derek Jacobi, Ben Chaplin, Hayley Atwell, Rob Brydon, Jana Perez, Alex Macqueen, Tom Edden
#2 Run All Night (2015)
URL: http://www.imdb.com/title/tt2199571?ref_=cht_bo_2
Weekend: $11.01M
Gross: $11.01M
Weeks: 1
Cast: Liam Neeson, Ed Harris, Joel Kinnaman, Boyd Holbrook, Bruce McGill, Genesis Rodriguez, Vincent D'Onofrio, Lois Smith, Common, Beau Knapp, Patricia Kalember, Daniel Stewart Sherman, James Martinez, Radivoje Bukvic, Tony Naumovski
#3 Kingsman: The Secret Service (2014)
URL: http://www.imdb.com/title/tt2802144?ref_=cht_bo_3
Weekend: $6.21M
Gross: $107.39M
Weeks: 5
Cast: Adrian Quinton, Colin Firth, Mark Strong, Jonno Davies, Jack Davenport, Alex Nikolov, Samantha Womack, Mark Hamill, Velibor Topic, Sofia Boutella, Samuel L. Jackson, Michael Caine, Taron Egerton, Geoff Bell, Jordan Long
【讨论】: