PHP While 循环 - 隐藏输入值 - SQL

Question

我试图一个接一个地显示许多行，下面有一个验证按钮，单击该按钮将转到更新（php）方法。我已经让它工作了，但是它总是相同的值（第一个字母姓氏）。

我需要尝试做的是让它在提交时从行中选择姓氏。代码如下：

<div class="container">
    <form action="update.php" method="POST">
        <?php
        //executes the SQL query
         $result = mysql_query("SELECT * FROM Sheet1");
         //returns the result from the database
         while ($row = mysql_fetch_array($result)) {
            $census = $row['Date'];
            $WebsiteAddress = $row['WebsiteAddress'];
            $LastName = $row['LastName'];

            echo "<input type='hidden' name='HiddenInput' value='".$LastName."'>";

            echo "<b>Last Name:</b> $LastName<br><br> <b>Website:</b> $WebsiteAddress<br><br> <b>Date:</b> $census<br><br>";

            echo "<input name='".$LastName."' type='submit' value='Verify' /><hr>";
         }
        ?>
    </form>
</div>

Answer 1

您需要创建输入数组以获取所有值，例如

<input type='hidden' name='HiddenInput[]' value='".$LastName."'>

然后 $_POST['HiddenInput'] 将返回包含所有 $LastName 值的数组

Answer 2

看看这段代码..为所有隐藏字段指定不同的名称..

 $i = 0;    
    while ($row = mysql_fetch_array($result)) {
                    $census = $row['Date'];
                    $WebsiteAddress = $row['WebsiteAddress'];
                    $LastName = $row['LastName'];

                    echo "<input type='hidden' name='HiddenInput_".$i."' value='".$LastName."'>";

                    echo "<b>Last Name:</b> $LastName<br><br> <b>Website:</b> $WebsiteAddress<br><br> <b>Date:</b> $census<br><br>";

                    echo "<input name='".$LastName."' type='submit' value='Verify' /><hr>";
                    $i++;
                 }