Python Selenium - 纯粹基于其基于身体元素偏移的位置单击元素

Question

我有一个问题在此处以某种方式进行了讨论 ([python][selenium] on-screen position of element)，但目前并没有达到我想要实现的目标。

我的目标如下： element.location 给出浏览器中元素左上角的位置。我有一个网站，即使它可能不是一个好的硒实践，我也希望能够完全根据它的位置点击这样的元素，因为它从来没有改变过，可能永远也不会改变。 假设 element.location 给出 {'x': 253, 'y': 584}，这是我迄今为止尝试的代码，没有运气

from selenium import webdriver
from selenium.webdriver.common.action_chains import ActionChains
driver.maximize_window()
url = "https://learn.letskodeit.com/p/practice"
driver.get(url)
open_window_elem = driver.find_element_by_id("openwindow")

# from wherever the mouse is, I move to the top left corner of the broswer
action = ActionChains(driver)
action.move_by_offset(-1000, -1000)    
action.click()
action.perform()

y_coordinate = open_window_elem.location["y"]
x_coordinate = open_window_elem.location["x"]

action = ActionChains(driver)
action.move_by_offset(x_coordinate, y_coordinate)
action.click()
action.perform()

当我运行这段代码时没有任何反应。我会打开一个新窗口。 有人可以帮忙吗？

Answer 1

在元素的中间点击比点击它的角落更好。有时角落不可点击。 “openwindow”元素的坐标 x 和 y 这些是其左上角的坐标。

我建议计算元素中心的坐标。为此，首先检查元素的宽度和高度：

from selenium import webdriver
from selenium.webdriver.common.action_chains import ActionChains
driver.maximize_window()
url = "https://learn.letskodeit.com/p/practice"
driver.get(url)

open_window_elem = "//button[@id='openwindow']"

x = int(driver.find_element_by_xpath(open_window_elem).location['x'])
y = int(driver.find_element_by_xpath(open_window_elem).location['y'])
width = int(driver.find_element_by_xpath(open_window_elem).size['width'])
height = int(driver.find_element_by_xpath(open_window_elem).size['height'])

action = webdriver.common.action_chains.ActionChains(driver)
action.move_by_offset(x + width/2, y + height/2)
action.click()
action.perform()

Answer 2

这是一个基于 (Clicking at coordinates without identifying element) 上可用的最后一个答案的解决方案，我不得不调整它，因为它在我以原始代码发布的网站上不起作用：

# WORKING EXAMPLE 3
# assumptions is I know what coordinate I want to use
# in this example we use x = 253, y = 584
# remember: y = 584 -> it will move down  (a negative value moves up)
zero_elem = driver.find_element_by_tag_name('body')
x_body_offset = zero_elem.location["x"]
y_body_offset = zero_elem.location["y"]
print("Body coordinates: {}, {}".format(x_body_offset, y_body_offset))

x = 253
y = 310

actions = ActionChains(driver)
actions.move_to_element_with_offset(driver.find_element_by_tag_name('body'), -x_body_offset, -y_body_offset).click()
actions.move_by_offset( x, y ).click().perform()

基本上，身体坐标不一定是 0,0，这就是我必须使用 x_body_offset 和 y_body_offset 的原因。

Answer 3

试试这个：

from selenium import webdriver
from selenium.webdriver.common.action_chains import ActionChains
driver.maximize_window()
url = "https://learn.letskodeit.com/p/practice"
driver.get(url)
open_window_elem = driver.find_element_by_id("openwindow")

# from wherever the mouse is, I move to the top left corner of the broswer
action = ActionChains(driver)
action.move_by_offset(-1000, -1000)    
action.click().perform()

y_coordinate = open_window_elem.location["y"]
x_coordinate = open_window_elem.location["x"]

action = ActionChains(driver)
action.move_by_offset(int(x_coordinate), int(y_coordinate))
action.click().perform()