【发布时间】:2021-02-10 09:14:31
【问题描述】:
我有一个 python GUI 分配,我必须在其中创建一个 GUI 应用程序,它将在指定的输入值范围内评估单个变量函数。我们必须使用类。我写了以下代码:
from tkinter import *
from matplotlib.figure import Figure
import matplotlib.pyplot as plt
from matplotlib.backends.backend_tkagg import (FigureCanvasTkAgg, NavigationToolbar2Tk)
import tkinter.font as font
class eval_interface:
def __init__(self):
self.root = Tk()
self.root.title("Function Evaluator")
self.topframe = Frame(self.root)
self.createTopFrame()
self.topframe.grid(row=0, column=0, columnspan=10, sticky=N + S + W + E)
self.frame2 = Frame(self.root)
self.createFrame2()
self.frame2.grid(row = 1, column = 0, pady = 15, columnspan = 10, sticky = N + S + W + E)
self.frame3 = Frame(self.root)
self.createFrame3()
self.frame3.grid(row=2, column=0, pady=15, columnspan=10, sticky=N + S + W + E)
self.frame4 = Frame(self.root)
self.frame5 = Frame(self.root)
self.createFrame5()
self.frame5.grid(row=4, column=0, pady=15, columnspan=10, sticky=N + S + E + W)
self.createFrame4()
self.frame4.grid(row = 3, column = 0, pady = 15, columnspan = 10, sticky = N+S+E+W)
self.root.mainloop()
def createTopFrame(self): #Frame containing title
title = Label(self.topframe, text="Function evaluator and plotter".center(228, " "), font=font.Font(size=17))
title.grid(row=0, column=0, columnspan=7)
def createFrame2(self): #Frame containing function Entry widget
title = Label(self.frame2, text = "Enter the function in x : ", font = font.Font(size = 14))
title.grid(row = 0, column = 0, sticky = N + S + W + E)
function_entry = Entry(self.frame2, width = 150)
function_entry.grid(row = 0, column = 1, sticky = N + S + W + E)
def createFrame3(self): #Frame containing range Entry widgets
range_label = Label(self.frame3, text="Enter the range of the function from : ", font = font.Font(size = 14))
lower_range_entry = Entry(self.frame3, width=10)
range_label2 = Label(self.frame3, text=" to ")
upper_range_entry = Entry(self.frame3, width=10)
range_label.grid(row=1, column=0, sticky="nsew")
lower_range_entry.grid(row=1, column=1)
range_label2.grid(row=1, column=2, sticky="nsew")
upper_range_entry.grid(row=1, column=3, sticky="nsew")
def createFrame4(self): #Frame containing button widgets
btn_evaluate = Button(self.frame4, text = "Evaluate", font = font.Font(size = 14), command = self.evaluate())
btn_plot = Button(self.frame4, text = "Plot", font = font.Font(size = 14))
btn_clear = Button(self.frame4, text = "Clear", font = font.Font(size = 14))
btn_exit = Button(self.frame4, text = "Exit", font = font.Font(size = 14), command = exit)
btn_evaluate.grid(row=0, column=0, padx=10, pady=5)
btn_plot.grid(row=0, column=1, padx=10, pady=5)
btn_clear.grid(row=0, column=2, padx=10, pady=5)
btn_exit.grid(row=0, column=3, padx=10, pady=5)
def createFrame5(self): #Frame containing Result Textbox
res_text = Text(self.frame5, width = 95, height = 55, padx = 10)
res_text.grid(row = 0, column = 0)
def evaluate(self):
x = 10
def clear(self):
z=12
eval_interface()
我的问题是,当单击“评估”按钮时,如何访问用户在三个条目小部件(在第 2 帧和第 3 帧中)中输入的数据?在我访问了数据并对其进行了必要的操作之后,如何在第 5 帧的文本框中显示结果? (我刚刚在评估和清除函数中编写了一些随机语句以查看输出 GUI。)
【问题讨论】: