如何使用循环最小化代码并且不应该重复随机数？

Question

我有 18 个游戏对象，我想将所有 18 个游戏对象定位在定义的随机位置。是的，我说定义的位置是因为我的游戏对象 z 位置只会随机变化，如 [0,60, 120, 180 等] 随机变化。请帮忙。

GameObject[] hurdles;
int randShared;

void Shart()
    {
        hurdles = GameObject.FindGameObjectsWithTag("Hurdles");
        randShared = Random.Range(0,19);

        if (randShared == 0)
        {
            hurdles[0].transform.position = new Vector3(0f, 0f, 0f);
            hurdles[1].transform.position = new Vector3(0f, 0f, 60f);
            hurdles[2].transform.position = new Vector3(0f, 0f, 120f);
            .
            .
            .
            hurdles[18].transform.position = new Vector3(0f, 0f, 120f);
        }

        if (randShared == 1)
        {
            hurdles[0].transform.position = new Vector3(0f, 0f, 120f);
            hurdles[1].transform.position = new Vector3(0f, 0f, 0f);
            hurdles[2].transform.position = new Vector3(0f, 0f, 60f);
            .
            .
            .
            hurdles[18].transform.position = new Vector3(0f, 0f, 120f);
        }

        if (randShared == 2)
        {
            hurdles[0].transform.position = new Vector3(0f, 0f, 60f);
            hurdles[1].transform.position = new Vector3(0f, 0f, 120f);
            hurdles[2].transform.position = new Vector3(0f, 0f, 0f);
            .
            .
            .
            hurdles[18].transform.position = new Vector3(0f, 0f, 120f);
        }

        .
        .
        .

        if (randShared == 18)
        {
            hurdles[0].transform.position = new Vector3(0f, 0f, 60f);
            hurdles[1].transform.position = new Vector3(0f, 0f, 120f);
            hurdles[2].transform.position = new Vector3(0f, 0f, 0f);
            .
            .
            .
            hurdles[18].transform.position = new Vector3(0f, 0f, 120f);
        }
    }

Answer 1

您可以循环您的范围并根据您的随机数以 60 的间隔创建一个偏移量。

for (var i = 0; i < 19; i++)
{
    var offset = i + randShared;
    if (offset > 18)
    {
        offset = offset - 19;
    }

    hurdles[i].transform.position = new Vector3(0f, 0f, (float)(offset * 60));

}

Answer 2

var rnd = new Random();
for (var i = 0; i < 19; i++)
    hurdles[i].transform.position = new Vector3(0f, 0f, 60f * rnd.Next(4)));