多级语音命令？

Question

我正在尝试做一个多级命令演讲，但我遇到了一些麻烦......

我想要主命令，例如：“TV”、“Light”、“water”等

例如，当我说“电视”时，我希望有子命令来执行所需的操作，例如：

当我说“电视”时：子命令->“调高音量”、“调低音量”、“关机”、“开机”

在我说“电视完成”之前，我只会得到识别的电视命令。然后我回到主命令的列表。

我该怎么做？

我的实际代码是这样的：

 class Program
    {
        static Dictionary<string, string> listaCanais = new Dictionary<string, string>()
            {
                { "Fox News", "0 6 0" },
                { "The Weather Channel", "0 3 1"},
                { "Spike", "0 3 8"}
            };
        static void Main(string[] args)
        {
            using (var sre = new SpeechRecognitionEngine(new System.Globalization.CultureInfo("pt-BR")))
            {
                sre.SetInputToDefaultAudioDevice();

                sre.LoadGrammarAsync(Comandos());

                sre.RequestRecognizerUpdate();
                sre.SpeechRecognitionRejected += sre_SpeechRecognitionRejected;
                sre.SpeechRecognized += sre_SpeechRecognized;

                sre.RecognizeAsync(RecognizeMode.Multiple);

                Console.ReadLine();
            }
        }

        public static Grammar Comandos()
        {
            Choices numerosTV = new Choices("zero", "um", "dois", "três", "quatro", "cinco", "seis", "sete", "oito", "nove", "10", "11", "12");

            GrammarBuilder fraseNumeroTV = new GrammarBuilder(numerosTV);

            GrammarBuilder fraseMudarCanal = new GrammarBuilder("TV, canal");
            fraseMudarCanal.Append(numerosTV);
            //fraseMudarCanal.Append(numerosTV);
            //fraseMudarCanal.Append(numerosTV);

            Choices nomeCanal = new Choices();

                      foreach (string key in listaCanais.Keys)
            {
                nomeCanal.Add(key);
            }

            GrammarBuilder fraseNomeCanal = new GrammarBuilder("TV, canal");
            fraseNomeCanal.Append(nomeCanal);

            GrammarBuilder fraseMudo = new GrammarBuilder("TV, silencioso");
            GrammarBuilder fraseLigar = new GrammarBuilder("TV, ligar");
            GrammarBuilder fraseFecharApp = new GrammarBuilder("Controle, fechar aplicativo");
            GrammarBuilder frasePauseComandoVoz = new GrammarBuilder("Controle, pausar comando de voz");
            GrammarBuilder fraseIniciarComandoVoz = new GrammarBuilder("Controle, ativar comando de voz");

            Choices opcoesPrincipais = new Choices(new GrammarBuilder[] {fraseMudarCanal,
                                                                         fraseNomeCanal,
                                                                         fraseMudo,
                                                                         fraseLigar,
                                                                         fraseFecharApp,
                                                                         frasePauseComandoVoz,
                                                                         fraseIniciarComandoVoz});

            Grammar resultado = new Grammar((GrammarBuilder)opcoesPrincipais);
            return resultado;

        }

        static void sre_SpeechRecognitionRejected(object sender, SpeechRecognitionRejectedEventArgs e)
        {
            Console.WriteLine("Ignorado");

        }

        // Create a simple handler for the SpeechRecognized event.
        static void sre_SpeechRecognized(object sender, SpeechRecognizedEventArgs e)
        {
            Console.WriteLine("Ouvi");

            if (e.Result == null)
                return;

            Console.WriteLine("[ " + e.Result.Confidence + " ]" + "Reconhecido: " + e.Result.Text);
        }
    }

提前致谢。

Answer 1

这样的事情在state machine framework 中很容易实现。您定义识别器的状态并根据它进行操作，主要工作在 onRecognitionResult 方法中完成：

states = {INPUT, TV, WATER};

inputGrammar = createInputGrammar();
tvGrammar = createTvGrammar();
waterGrammar = createWaterGrammar();

state = INPUT;

vodi onRecognitionResult() {

   if (state == INPUT) {
        if (result == "TV") {
            state = TV;
            recognizer.loadGrammar(tvGrammar);
        }
   }
   if (state == TV) {
        if (result == "Volume UP") {
            raiseVolume();
        }
        if (result == "TV done") {
            state = INPUT;
            recognizer.loadGrammar(inputGrammar);
        }
    }
    // Restart recognition
    recognizer.recognizeAsync();
}

您可以阅读Simple state machine example in C#?了解更多信息。