【发布时间】:2011-04-16 04:02:54
【问题描述】:
我对 php/SQL 很陌生(1 天),所以如果我以向后的方式这样做,请原谅我。
下面的这个 php 旨在将 100 个最近的条目返回到数据库中。我尝试通过选择要返回的 100 个条目并按输入的日期(时间戳)排序来做到这一点。这会将 100 个最近的条目返回到数据库吗?还是我理解错了?
$type = isset($_GET['type']) ? $_GET['type'] : "global";
$offset = isset($_GET['offset']) ? $_GET['offset'] : "0";
$count = isset($_GET['count']) ? $_GET['count'] : "100";
$sort = isset($_GET['sort']) ? $_GET['sort'] : "date DESC";
// Localize the GET variables
$udid = isset($_GET['udid']) ? $_GET['udid'] : "";
$name = isset($_GET['name']) ? $_GET['name'] : "";
// Protect against sql injections
$type = mysql_real_escape_string($type);
$offset = mysql_real_escape_string($offset);
$count = mysql_real_escape_string($count);
$sort = mysql_real_escape_string($sort);
$udid = mysql_real_escape_string($udid);
$name = mysql_real_escape_string($name);
// Build the sql query
$sql = "SELECT * FROM $table WHERE ";
switch($type) {
case "global":
$sql .= "1 ";
break;
case "device":
$sql .= "udid = '$udid' ";
break;
case "name":
$sql .= "name = '$name' ";
break;
}
$sql .= "ORDER BY $sort ";
$sql .= "LIMIT $offset,$count ";
$result = mysql_query($sql,$conn);
if(!$result) {
die("Error retrieving scores " . mysql_error());
}
//echo $result;
$rows = array();
while($row = mysql_fetch_assoc($result)) {
$rows[] = $row;
}
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