MySQL按两列分组

Question

我有一个表格，其中列出了针对订单的费用以及与订单关联的发票 ID。

orderID、financialType、invoiceID

我希望获取所有具有 financeType='17' 但具有不同 invoiceID 的订单

示例表：

orderID     financialType       invoiceID
123000      10                  NULL
123000      17                  900
123000      17                  901
123111      17                  902
123111      17                  902
123222      10                  NULL
123333      17                  900
123444      17                  900
123444      17                  901
123444      17                  902

在这种情况下，我对 123000（开 2 张不同发票）和 123444（开 3 次发票）感兴趣。

我目前的查询是：

SELECT orderID, count(*) as freq FROM orders WHERE financialType='17' group by orderID, invoiceID having freq > 1 order by freq desc

但这是给我每个订单的总收费次数，而不是在不同发票上收费的次数。在我的示例中，我不关心 123111 - 这被收取了两次费用，但在同一张发票上，这很好。

我希望看到：

orderID  freq
123000  2
123444  3

Answer 1

此查询有效：

SELECT orderID, GROUP_CONCAT(invoiceID), count(DISTINCT invoiceID) as freq 
FROM orders 
WHERE financialType='17' 
group by orderID 
having freq > 1
order by freq desc

http://sqlfiddle.com/#!2/c2cc07/6

Answer 2

SELECT 
count(orderID) as freq, orderID , invoiceID 
FROM orders  
WHERE financialType='17' 
group by orderID 
having freq > 1 
order by orderID desc

http://sqlfiddle.com/#!2/794ff/5 上的演示

使用

SELECT 
count(orderID) as freq, orderID , GROUP_CONCAT(invoiceID) as invoiceIDs 
FROM orders 
WHERE financialType='17' 
group by orderID 
having freq > 1 
order by orderID desc

如果您还想查看订单的所有发票 ID

http://sqlfiddle.com/#!2/794ff/9的演示

Answer 3

试试：

  SELECT orderID, count(*) as freq 
  FROM orders WHERE financialType='17'
  GROUP BY orderid
  HAVING count(*)>1

或者如果您想要一张独特的发票：

  SELECT orderID, count(DISTINCT invoiceID) as freq 
  FROM orders WHERE financialType='17'
  GROUP BY orderid
  HAVING count(*)>1