如何在 Visual Studio 构建前/构建后命令行中检测调试/发布？答案

【问题标题】：How to detect debug/release in visual studio pre/post-build command line?如何在 Visual Studio 构建前/构建后命令行中检测调试/发布？
【发布时间】：2011-08-18 23:55:26
【问题描述】：

如何从命令行 pre-build 或 post-build 窗口检测 Debug 或 Release 模式?

我测试了下面的代码，它在代码文本窗口中工作。它可以转换为命令行代码吗？如果可以，怎么做，谢谢。

bool debugging = false;
#if DEBUG
    debugging = true;
    // do something like to move ../debug/bin/ to somewhere.
#else
    debugging = false;
    // do something like to move ../debug/bin/ to somewhere.
#endif

Console.WriteLine(debugging);

【问题讨论】：

标签： c# visual-studio c#-2.0 pre-build-event post-build-event

【解决方案1】：

您可以检查$(ConfigurationName) 变量的值。

它与您在代码示例中使用的不同。 #if DEBUG 是一个条件编译指令，它取决于 DEBUG 是否已被定义为符号。 ConfigurationName 变量取决于您指定的构建配置（与条件编译符号无关）。

【讨论】：

【解决方案2】：

echo **** Visual Studio PREBUILD... **** 
echo **** Remember these are running from command line, aka BATCH commands 
echo **** watch out (include) single space after the conditional (and other ridiculous traps and pitfalls)
echo **** so I HIGHLY recommend getting out of BATCH and into Powershell as soon as possible.  Make prebuild a one-liner and then put additional code in your powershell... (you will thank me later)
echo **** Read more about why I'd rather claw my eyes out than program in BATCH here: https://www.tutorialspoint.com/batch_script/batch_script_if_else_statement.htm

if "Debug" == $(ConfigurationName) (
  echo OPTIONALLY just pass in the Configuration name and do all the logic and checking INSIDE the powershell.  Seriously, it is way better.
  powershell .\DevBox.Prebuild.ps1 -Config:$(ConfigurationName)
)

echo *** Much better to just check for Debug INSIDE the powershell
powershell .\DevBox.Prebuild.ps1 -Config:$(ConfigurationName)

【讨论】：