捕捉 http.call 超时异常

Question

此 Meteor 服务器代码使用 http@1.2.8，在慢速互联网连接期间，它会在终端上打印以下内容：

response = HTTP.call(method, url, {
  timeout: 30000,
  headers: header,
  content: content,
  followRedirects: true
});

异步函数回调异常：错误：ETIMEDOUT 在 Object.Future.wait (/abc/xyz/.meteor/packages/meteor-tool/.1.4.0.i9pn2o++os.osx.x86_64+web.browser+web.cordova/mt-os.osx.x86_64 /dev_bundle/server-lib/node_modules/fibers/future.js:449:15)

如何优雅地捕获此错误以便通知客户？谢谢

Answer 1

只需使用 try catch

try{
    response = HTTP.call(method, url, {
        timeout: 30000,
        headers: header,
        content: content,
        followRedirects: true
    });
}
catch(e){
    if(e.code==="ETIMDOUT"){
        //alert the client
    }
}