【发布时间】:2020-12-06 12:02:05
【问题描述】:
我已将 Spring Security 集成到我的项目中,并且我之前使用 hibernate 验证用户详细信息。现在我必须使用 CAS 来完成。 这是我当前的 Spring security.xml
<?xml version="1.0" encoding="UTF-8"?>
<beans:beans xmlns="http://www.springframework.org/schema/security"
xmlns:beans="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xmlns:aop="http://www.springframework.org/schema/aop"
xmlns:context="http://www.springframework.org/schema/context"
xsi:schemaLocation="
http://www.springframework.org/schema/aop http://www.springframework.org/schema/aop/spring-aop.xsd
http://www.springframework.org/schema/context http://www.springframework.org/schema/context/spring-context.xsd
http://www.springframework.org/schema/jee http://www.springframework.org/schema/jee/spring-jee.xsd
http://www.springframework.org/schema/lang http://www.springframework.org/schema/lang/spring-lang.xsd
http://www.springframework.org/schema/tx http://www.springframework.org/schema/tx/spring-tx.xsd
http://www.springframework.org/schema/util http://www.springframework.org/schema/util/spring-util.xsd
http://www.springframework.org/schema/mvc
http://www.springframework.org/schema/mvc/spring-mvc-3.0.xsd
http://www.springframework.org/schema/beans
http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/security
http://www.springframework.org/schema/security/spring-security-3.1.xsd
">
<global-method-security pre-post-annotations="enabled" />
<http pattern="/css/**" security="none"/>
<http pattern="/images/**" security="none"/>
<http pattern="/js/**" security="none"/>
<http pattern="/index.jsp" security="none"/>
<http pattern="/app/addNewUser.json" security="none"/>
<http pattern="/dbcomplogin.jsp" security="none"/>
<http pattern="/loggedout.jsp" security="none"/>
<http use-expressions="true">
<!--
Allow all other requests. In a real application you should
adopt a whitelisting approach where access is not allowed by default
-->
<intercept-url pattern="/**" access="isAuthenticated()" />
<form-login login-page='/dbcomplogin.jsp'
authentication-failure-url="/dbcomplogin.jsp?login_error=1"
default-target-url="/index.jsp" />
<logout logout-success-url="/loggedout.jsp" delete-cookies="JSESSIONID"/>
<remember-me />
</http>
<beans:bean id="myUserService" class="com.tcs.ceg.services.impl.UserServiceImpl" />
<authentication-manager>
<authentication-provider user-service-ref="myUserService" />
</authentication-manager>
</beans:beans>
在 UserServiceImpl 类“loadUserByUsername”方法中,我使用 Hibernate 调用从数据库中获取用户详细信息,如果数据库中存在用户名、密码,则返回它们。
但现在我必须使用 CAS server 来完成。请告诉我我需要在 spring-security.xml 中更改的所有内容,这样,如果用户未通过身份验证,则将打开 CAS 服务器的登录页面,并在单击注销时进行单次注销和 CAS 的注销页面服务器将打开。 我是 CAS 和 Spring Security 的新手,请帮助我。
【问题讨论】:
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请停止多次发布同一个问题。
标签: java spring-security cas