ORACLE - 如何从一列中显示 3 个不同的值

Question

我有一个包含 4 种类型的表和一个“值”列，我需要在单个查询中为每个 id 显示 3 列。 类型 1= abc，类型 2= def，类型 3= ghi，类型 4= jkl 我当前的查询，现在在单个列中显示所有值，我需要每个 typeid 一个列，将是 4 个具有不同名称的列

SELECT 
 OBJECTID
,TRUNC(DATETIME + 1 / (24 * 12), 'HH24') DATETIME
,TIMEZONE
,VALUE as value
,LOADID LOADID
FROM PROD.TS_WSI_HOURLY_OBSERVATION
where typeid in(1,2,3,4);

id	value
1	50
2	30
3	20
4	85

我需要如何显示这种结果：

abc	def	ghi	jkl
50	30	20	85.
15	10	4	34.
34	30	12	8598

知道怎么做吗？我需要所有的行，而不是像 max 这样的聚合

问候

Answer 1

这就是我们通常的做法：

SQL> with temp (gbc, id, value) as
  2    -- sample data
  3    (select 'a', 1, 50 from dual union all
  4     select 'b', 1, 15 from dual union all
  5     select 'c', 1, 34 from dual union all
  6     --
  7     select 'a', 2, 30 from dual union all
  8     select 'b', 2, 10 from dual union all
  9     select 'c', 2, 30 from dual union all
 10     --
 11     select 'a', 3, 20 from dual union all
 12     select 'b', 3,  4 from dual union all
 13     select 'c', 3, 12 from dual
 14    )
 15  select gbc,
 16         sum(case when id = 1 then value end) as abc,
 17         sum(case when id = 2 then value end) as def,
 18         sum(case when id = 3 then value end) as ghi,
 19         sum(case when id = 4 then value end) as jkl
 20  from temp
 21  group by gbc;

GBC        ABC        DEF        GHI        JKL
--- ---------- ---------- ---------- ----------
a           50         30         20
b           15         10          4
c           34         30         12

SQL>

---

或者，如果我理解您的查询，您只需将其用作 CTE 并提取所需的值：

with temp as
  (select 
      typeid,
      objectid
     ,trunc(datetime + 1 / (24 * 12), 'HH24') datetime
     ,timezone
     ,value as value
     ,loadid loadid
   from prod.ts_wsi_hourly_observation
   where typeid in(1,2,3,4)
  )
select sum(case when typeid = 1 then value end) as abc,  
       sum(case when typeid = 2 then value end) as def,
       sum(case when typeid = 3 then value end) as ghi,
       sum(case when typeid = 4 then value end) as jkl
from temp
group by objectid;