为每个不同的外键选择第二大值

Question

所以，我有两个表，帐户和发票，它们由帐户表中的主键链接，即。 account.key 和 invoice.key。

我想为每个帐户的第二个最新发票日期选择 account.accountnumber、invoice.invoicedate、invoice.invoiceamount。

有什么想法吗？

所以要选择所有发票及其对应的帐号：

select a.accountnumber, i.invoicedate, i.invoiceamount
from account a
join invoice i on (a.key = i.key)

并从整个发票表中选择第二张最新发票：

select MAX(invoicedate) from INVOICE i where invoicedate NOT IN (SELECT MAX(invoicedate) from i

但是我如何从 invoice 表中获取每个帐户的第二张最新发票，以及 account 表中的帐号？

提前致谢。

Answer 1

通过使用ROW_NUMBER() 窗口函数...

select accountnumber, invoicedate, invoiceamount 
from 
(
    select a.accountnumber, i.invoicedate, i.invoiceamount, 
        row_number() over (partition by a.accountnumber order by invoicedate desc) rn
    from account a 
        join invoice i on a.[key] = i.[key]
) v
where rn = 2

Answer 2

尝试使用这个：

select a.accountnumber, i.invoicedate, i.invoiceamount 
from account a 
join invoice i on a.[key] = i.[key]
and i.invoicedate in
(select max(invoicedate) as secondmaxdate from invoice where invoicedate not in
(select max(invoicedate) as maxdate from invoice group by [key])
group by [key])